All categories

2 years ago

What’s the distance from the nucleus of an atom to its theoretical outer edge of electron orbits

Chemistry

1 answer:

ollegr [7]2 years ago

4 0

Answer:

The range of atoms = (30-300 pm) depending upon the element

Explanation:

The Atomic radii of the atom is the distance from the center of the circle to the outermost orbital.

The center of the circle is the nucleus and the radii is the outermost boundary.

The actual size of the atom is decided on the basis of the Zeff . Also known as effective nuclear charge.

Zeff: It is the net positive charge felt by the outermost electron by the nucleus.

The value of Zeff depends upon the shielding constant. More the shielding less will be the Zeff . Hence the size of the atom increases.

Due to shielding the outermost electrons feel less pull of nucleus.

The greater the Zeff , the smaller the radius of the atom.

The formula used to calculate the atomic mass is :

$r_{n}=\frac{52.9n^{2}}{Z}$ pm

Here "pm"= picometers

$1 pm = 10^{-12}m$

The size of the smallest atom H-atom = 120 pm

The range of atoms = (30-300 pm)

You might be interested in

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

Answer: The concentration of $NH_3$ required will be 0.285 M.

Explanation:

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago

What the atmosphere mean

Alex_Xolod [135]

The envelope of gases surrounding the earth or another planet.

3 0

3 years ago

How to know how many valence electrons are in an element

Alenkinab [10]

Answer:

Hope it helped

Explanation:

For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.

7 0

3 years ago

What is the molarity of a solution with 23 moles of solute, and 100 ml of a solvent?

Marina CMI [18]

Molarity is calculated by using following formula,

Molarity = Moles / Volume

Data Given:
Moles = 23 moles

Volume = 100 ml ÷ 1000 = 0.1 L

Putting values in eq. 1,

Molarity = 23 mol / 0.1 L

Molarity = 230 mol/dm³

Result:
When 23 mol of solute is dissolved in a solvent to make a solution of 100 ml, then it will have a Molarity of 230 mol/dm³.

3 0

3 years ago

According to le châtelier’s principle, the amount of solid reactant or product present does not have an impact on the equilibriu

Inessa05 [86]

The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium

What is Le Chatelet's Principle ?

The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.

According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.

To know about Le Chatelet's Principle from the link

brainly.com/question/2943338

#SPJ4

5 0

7 months ago