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allochka39001 [22]
3 years ago
12

A ball is launched from a spring on the floor with an initial velocity of 32 m/s. it then comes to a stop in 4.3 seconds. Determ

ine the acceleration of the ball.
Chemistry
1 answer:
monitta3 years ago
3 0

Answer:

-7.4m/s2

Explanation:

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Answer: D) 1 lone pair, square pyramidal

Explanation:

Formula used  : \text{Number of electrons}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom  = 7

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Now we have to determine the hybridization of the IF_5  molecule.

\text{Number of electrons}=\frac{1}{2}\times [7+5+0-0]=6

Bond pair electrons = 5

Lone pair electrons = 6-5 = 1

The number of electrons are 6 that means the hybridization will be sp^3d^2 and the electronic geometry of the molecule will be octahedral .

But as there are five atoms around the central iodine atom, the sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square pyramidal.

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