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lesantik [10]
3 years ago
6

When is an isotope considered stable? (Select all that apply.)

Chemistry
1 answer:
GaryK [48]3 years ago
6 0

Explanation:

A stable isotope is one that does not emit radiation, or, if it does its half-life is too long to have been measured. It is believed that the stability of the nucleus of an isotope is determined by the ratio of neutrons to protons.

Hope this helps you out : D

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What do cyanobacteria use to produce energy and by what process do they produce energy
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As they contain, green pigement they can perform "Photosynthesis" and obtains energy from that process

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What is C6H5 called?
zysi [14]
C6H5 is the molecular formula for Phenyl.
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Read 2 more answers
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
2 years ago
What is the usable form of nitrogen that is found in the ground?
laila [671]
Nitrate

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5 0
3 years ago
Use the following scenario to answer the question: A cell has an antiport protein on its apical surface. The cell is placed in a
balu736 [363]

Answer:

The correct answer is "Secondary active transport".

Explanation:

Secondary active transport is a form of across the membrane transport that involves a transporter protein catalyzing the movement of an ion down its electrochemical gradient to allow the movement of another molecule or ion uphill to its concentration/electrochemical gradient. In this example, the transporter protein (antiporter), move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. The 3 Na⁺ are the ions moved down its electrochemical gradient and the one Ca⁺⁺ is the ion moved uphill its electrochemical gradient, because Na+ and Ca⁺⁺are more concentrated in the solution than inside the cell. Therefore, this scenario is an example of secondary active transport.

6 0
3 years ago
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