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3 years ago

7

10.0g of calcium carbonate was heated. The mass of calcium oxide left was 5.6g. Calculate the mass of carbon dioxide produced in

the reaction.

1 answer:

jarptica [38.1K]3 years ago

6 0

Hope it cleared your doubt.

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Please help me thanks so much??!!.:;))..I will mark you:))

zubka84 [21]

D for sure hope this helps

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3 years ago

Read 2 more answers

Will mark as Brainliest.

8090 [49]

The answer is A) Aluminum chloride - It does not have the prefix "tri-" since it is ionic.

3 0

3 years ago

Sunlight is more spread out as you move away from the equator.

suter [353]

Answer:

False.

Explanation:

<u>The given statement asserts a false claim because the equator is the region that receives maximum sunlight</u>. The equator is placed right below the sun and thus, it tends to receive the maximum radiation across the year. While the poles are the coldest regions of the Earth because due to Earth's titled axis, they receive very few sun rays for a certain time of the year. Thus, <u>if we move away from the equator, we are likely to receive less radiation from the sun as the sun keeps getting farther while moving away from the equator</u>.

3 0

3 years ago

A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 64.0 mL of 0.0600 M EDTA . Titration of the excess unreacted EDTA req

tigry1 [53]

Answer:

the concentration of $Cd^{2+}$ in the original solution= 0.0088 M

the concentration of $Mn^{2+}$ in the original solution = 0.058 M

Explanation:

Given that:

The volume of the sample containing Cd2+ and Mn2+ = 50.0 mL; &

was treated with 64.0 mL of 0.0600 M EDTA

Titration of the excess unreacted EDTA required 16.1 mL of 0.0310 M Ca2+

i.e the strength of the Ca2+ = 0.0310 M

Titration of the newly freed EDTA required 14.2 mL of 0.0310 M Ca2+

To determine the concentrations of Cd2+ and Mn2+ in the original solution; we have the following :

Volume of newly freed EDTA = $\frac{Volume\ of \ Ca^{2+}* Sample \ of \ strength }{Strength \ of EDTA}$

= $\frac{14.2*0.0310}{0.0600}$

= 7.3367 mL

concentration of $Cd^{2+}$ = $\frac{volume \ of \ newly \ freed \ EDTA * strength \ of \ EDTA }{volume \ of \ sample}$

= $\frac{7.3367*0.0600}{50}$

= 0.0088 M

Thus the concentration of $Cd^{2+}$ in the original solution = 0.0088 M

Volume of excess unreacted EDTA = $\frac{volume \ of \ Ca^{2+} \ * strength \ of Ca^{2+} }{Strength \ of \ EDTA}$

= $\frac{16.1*0.0310}{0.0600}$

= 8.318 mL

Volume of EDTA required for sample containing $Cd^{2+}$ and $Mn^{2+}$ = (64.0 - 8.318) mL

= 55.682 mL

Volume of EDTA required for $Mn^{2+}$ = Volume of EDTA required for

sample containing $Cd^{2+}$ and

$Mn^{2+}$ -- Volume of newly freed EDTA

Volume of EDTA required for $Mn^{2+}$ = 55.682 - 7.3367

= 48.3453 mL

Concentration of $Mn^{2+}$ = $\frac{Volume \ of EDTA \ required \ for Mn^{2+} * strength \ of \ EDTA}{volume \ of \ sample}$

Concentration of $Mn^{2+}$ = $\frac{48.3453*0.0600}{50}$

Concentration of $Mn^{2+}$ in the original solution= 0.058 M

Thus the concentration of $Mn^{2+}$ = 0.058 M

6 0

3 years ago

What does ph measure? 6. msg behaves as a buffer. what is a buffer? 7. if we are interested in understanding how msg behaves as

Ket [755]

1. Answer;

- pH of a solution is the measures of molar concentration of hydrogen ions in a solution.

Explanation;

-pH is a measure of how acidic/basic a substance is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in a substance.

-The pH value states the relative quantity of hydrogen ions (H+) contained in a solution. The greater the concentration of H+ the more acidic the solution and the lower the pH.

2. Answer;

Buffer is a substance that minimizes change in concentrations of H+ and OH- in a solution.

Explanation;

-A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.

-A buffer can resist pH change upon the addition of an acidic or basic components. It is able to neutralize small amounts of added acid or base, thus maintaining the pH of the solution relatively stable.

3. Answer;

By combining the two substances, we can analyze how the buffers react and stabilize the pH in the solution

Explanation;

- We found out that MSG was a buffer, and since it was a buffer more hydrogen ions is added to the solution. When we added it to the solution, it became a solid, which was what precipitated.

-There were a lot of Hydrogen protons floating around and with the MSG precipitate, we have all of these floating hydrogen and hydroxide ions. These hydrogens and hydroxide ions attach to the MSG, and the extra hydrogens would help to form the precipitate.

6 0

3 years ago