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dimulka [17.4K]

2 years ago

14

A basketball is held over head at a height of 2.4 m. The ball is lobbed to a teammate at 8 m/s at an angle of 40'. If the ball i

s caught at the same height it was tossed at, how far away is the teammate?

1 answer:

cupoosta [38]2 years ago

7 0

Explanation:

since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.

We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.

range can be calculated by the formula :-

$\boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }}$

u is the velocity during its take off and $\theta$ is the angle at which its thrown

Given that

u = 8m/ s
$\theta$ = 40°

calculating range using the above formula

$= \frac{ {8}^{2} \sin2(40) }{10}$

$= \frac{64 \times \sin(80) }{10}$

value of sin 80 = 0. 985

$= \frac{64 \times 0.985}{10}$

$= \frac{63.027}{10}$

$= 6.3027$

Hence,

$\mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } }$

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2 years ago

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Answer:

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Explanation:

Part a

From definition a transverse wave is which one where the elements moves perpendicular to the direction of the wave. For example is a wave is moving from the left to the right the elements would be wibrating or moving upward or downward.

We have a lot examples for a transverse wave. For example water waves, strings on the musical instruments , light and radio waves.

Part b

We can identify a transverse wave if the particles are displaced perpendicular to the direction of the wave. Usually these types of wave occur in elastic solids. And we can identify it when we see a pattern perpendicular between the wave direction and the particles motion. In simple words we need to see that the wave is moving down and up.

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