Question

Really need help with this Physics question!

Answer 1

As we know that block of steel is continue to be in moving state

so here the friction must be kinetic friction between two surface

so we know that formula of kinetic friction must be

$F_k = \mu_k mg$

now we have

$\mu_k = 0.57$

$mg = 25 N$

now from the above equation we have

$F_k = 0.57\times 25$

$F_k = 14.25 N$

So here we need atleast 14.25 N force to continue sliding the box now as per given options all forces which are less than 14.25 N is not correct

Hence correct answer must be 18.0 N

D) 18.0 N