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Luda [366]
4 years ago
7

Use the virtual lab to prepare 150.0 ml of an iodine solution with a concentration of 0.06 g/ ml from the bottle of 0.12g/ml iod

ine solution
Chemistry
1 answer:
son4ous [18]4 years ago
8 0

Answer:

Explanation:

In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g

Let volume of given concentration of .12 g / ml required be V

In volume V , gram of iodine = V x .12 g

According to question

V x .12 = 9 g

V = 9 / .12 = 75 ml

So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .

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Which type of weathering helped to form barrier islands
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Students are designing an experiment to test the law of conservation of mass using the following materials: 10 g baking soda, 30
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A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.
daser333 [38]

Answer:

1.429 g of  N₂

Explanation:

The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:

  • N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆  2NH₃ ₍g₎  

One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.

We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.

no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol

and the actual yield is 98% , then the theoretical number of moles that would be produced are:  

  • percent yield = (actual yield / theoretical yield) × 100

98 = (0.1 mol /  theoretical yield) × 100

theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol

using cross multiplication

1 mol of N₂ → 2 mol of NH₃.

?? mol of N₂ → 0.102 mol of NH₃.

no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol

Last step is to convert the moles back to grams using:

mass = (no of moles of N₂  * molar mass of N₂)

         = (0.051 mol * 28 g/mol) = 1.429 g

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4 years ago
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