Answer:
The motorcycle travelled 69.73 m during these 3.1 s.
Explanation:
In order to calculate the distance that the motorcycle travelled we first need to obtain the acceleration rate that was used to brake the vehicle. We do that by using the following formula:
a = (V_final - V_initial)/(t) = (15 - 30)/(3.1) = -4.84 m/s^2
The distance is given by the following formula:
S = (V_final^2 - V_initial^2)/(2*a)
S = (15^2 - 30^2)/[2*(-4.84)] = (225 - 900)/(-9.68) = -675/(-9.68) = 69.73 m
The motorcycle travelled 69.73 m during these 3.1 s.
Answer:
the force it exert on track is
46600N
Explanation:
The car acceleration
a = V²/R
= (18.0m/s)²/(24.0)
= 13.5m/s²
net force
F(net) = m * a
= 2000kg * 13.5m/s²
= 27000N
F(net) = F₀ - F₁
where
F₀ = upward force
F₁ = downward force
F₁ = m * g
= (2000kg) * (9.8m/s²)
= 19600N
upward force which is F₀
F₀ = F(net) + F₁
= 27000N + 19600N
= 46600N
As per bernoulli's principle
here
= pressure upwards
= pressure downwards
= velocity of air upwards
= velocity of air downwards
now from this equation we can say that the pressure difference will be
now the force due to this pressure difference will be
so this is the above force which is given above
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