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3 years ago

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A small mailbag is released from a helicopter that is descending steadily at 2.52 m/s. (a) After 4.00 s, what is the speed of th

e mailbag

1 answer:

gogolik [260]3 years ago

6 0

Answer: 41.72m/s

Explanation: v= u + gt

V = 2.52 + 9.8(4.00)

V = 41.72m/s

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The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i

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Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius= $r=\frac{d}{2}=\frac{2.3}{2}=1.15 m$

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency= $\frac{1200}{60}=20 Hz$

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4 years ago

Action-reaction forces do not cancel each other because the action force is always greater than the reaction force

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EMERGENCY!! Doing my Physics homework now and I need help on this one please - all information provided, I'd be very VERY gratef

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(b) Vertical:

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Horizontal:

$v_x = 30\frac{m}{s}\cos 40^\circ = 23.0 \frac{m}{s}$

(c) Use the kinematic equation for distance. Calculate only the vertical component (horizontal is irrelevant):

$s_y = -\frac{1}{2}gt^2 +vt\,,\,\,\,s_y=0\\0 = -\frac{1}{2}gt^2 +vt\\\frac{1}{2}gt =v\\t = \frac{2v}{g}= \frac{2\cdot30\sin 40^\circ\frac{m}{s}}{9.8\frac{m}{s^2}}=3.9s$

The ball will be in the air for about 3.9 s.

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$s_x = 23\frac{m}{s}\cdot 3.9 s = 89.7m$

The range is 89.7 meters.

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3 years ago

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Answer:

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