A small mailbag is released from a helicopter that is descending steadily at 2.52 m/s. (a) After 4.00 s, what is the speed of th
e mailbag
1 answer:
Answer: 41.72m/s
Explanation: v= u + gt
V = 2.52 + 9.8(4.00)
V = 41.72m/s
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