Answer:
D
Explanation:
Scientists use significant figures to avoid claiming more accuracy in a calculation than they actually know.
Answer:
F= 5.71 N
Explanation:
width of door= 0.91 m
door closer torque on door= 5.2 Nm
In order to hold the door in open position we need to exert an equal and opposite torque, to the door closer torque, on the door.
so wee need to exert 5.2 Nm torque on the door.
If we want to apply minimum force to exert the required torque we need to apply force perpendicularly on the door knob (end of door) so that to to greater moment arm.
T= r x F
T= r F sin∅
F= T/ (r * sin∅)
F= 5.2/ (0.91 * 1)
F= 5.71 N
The force acting on the cart is 1.43 N.
<h3>What is force?</h3>
Force can be defined as the product of mass and acceleration.
To calculate the force acting on the cart, we use the formula below.
Formula:
- F = m(v-u)/t................. Equation 1
Where:
- F = Force acting on the cart
- m = mass of the cart
- v = Final velocity
- u = initial velocity
- t = time
From the question,
Given:
- m = 500 g = 0.5 kg
- v = 30 m/s
- u = 10 m/s
- t = 7 seconds
Substitute these values into equation 1
- F = 0.5(30-10)/7
- F = 10/7
- F = 1.43 N.
Hence, the force acting on the cart is 1.43 N.
Learn more about force here: brainly.com/question/13370981
Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]
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