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Leto [7]
3 years ago
11

A diatomic molecule with a triple covalent bond is

Chemistry
2 answers:
Novosadov [1.4K]3 years ago
6 0

Nitrogen is a diatomic molecule in the VA family on the periodic table. Nitrogen has five valence electrons, so it needs three more valence electrons to complete its octet. A nitrogen atom can fill its octet by sharing three electrons with another nitrogen atom, forming three covalent bonds, a so-called triple bond.

Hope I helped :)

-Bucky

Debora [2.8K]3 years ago
5 0
The diatomic molecule with a triple covalent bond is N2.
Nitrogen has five atoms in its valence shell. In order for it to attain the octet structure, that is, to have eight electrons in its outermost shell, it has to donate three electrons, just like the other element it is reacting with in order to form a triple covalent bond.
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A first-order reaction has a half-life of 20.0 minutes. Starting with 1.00 × 1020 molecules of reactant at time t = 0, how many
zalisa [80]

Half-life time of a reaction is time at which reactant concentration becomes half of its initial value.

Half-life of the first order reaction is 20 min. Rate constant can be calculated as follows:

K=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{20 min}=0.03466 min^{-1}

The rate expression for first order reaction is as follows:

k=\frac{2.303}{t}log\frac{A_{0}}{A_{t}}

initial number of molecules of reactant are 10^{20}, time is 100 min thus, putting the values to calculate number of reactant at time 100 min,

0.03466 min^{-1}=\frac{2.303}{100 min}log\frac{[10^{20}]}{A_{t}}

On rearranging,

\frac{10^{20}}{A_{t}}=31.988

Or,

A_{t}=3.13\times 10^{18}

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7 0
3 years ago
What mineral property is illustrated by this photograph?​
lbvjy [14]
<h2>Hardness, lustre, and colour.</h2>

Explanation:

These Rocks shown in photographs are made of different types of minerals which have properties as follows:

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3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
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Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

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Your answer is D. :)
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