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BartSMP [9]
3 years ago
14

A polystyrene component must not fail when a tensile stress of 1.25 MPa (180 psi) is applied. Determine the maximum allowable su

rface crack length if the surface energy of polystyrene is 0.50 J/m2 (2.86 103 in.-lbf/in.2 ). Assume a modulus of elasticity of 3.0 GPa (0.435 106 psi).

Physics
2 answers:
torisob [31]3 years ago
6 0

Answer:

Maximum allowable surface crack length =  l =  0.000611m

Explanation:

Tensile stress = σ = 1.25 MPa = 1.25 × 10^6 N/m2

Surface energy of polystyrene = Es = 0.50 J/m2

Elastic Mudolus = E = 3 GPa = 3 × 10^9 N/m2

Maximum allowable surface crack length = l = ?

We know that:

       l = 2EEs/πσ^2 ....... (i)

By putttin the values in equation (i)

       l = (2)(0.50)(3 × 10^9)/(3.14)(1.25 × 10^6)^2

       l =  0.000611m

Hence, the Maximum allowable surface crack length will be 0.000611m.

Scorpion4ik [409]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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earnstyle [38]

The maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

<h3>Net force on the box</h3>

The net force on the box can be used to determine the maximum number of cubes that can be stacked without sliding.

The stack cubes must be at equilibrium.

∑Fx = 0

nW - μFₙ = 0

where;

  • n is number of the cubes
  • Fₙ is the normal force of the cubes
  • W is the weight of the cubes acting parallel to the plane

n(mg)sinθ - μmgcosθ = 0

n(mg)sinθ  = μmgcosθ

nsinθ  = μcosθ

  • let the coefficient of friction = 1

nsinθ  = cosθ

n = cosθ/sinθ

n = 1/tanθ

n = (1)/(1/8)

n = 8

Thus, the maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

Learn more about cubes here: brainly.com/question/1972490

#SPJ1

7 0
2 years ago
What is the pressure in a gas container that is connected to an open-end U-tube manometer if thepressure of the atmosphere is 75
VARVARA [1.3K]

Answer:

The pressure in a gas container  is 839.44mmHg

Explanation:

Density of Mercury = 13.56g/cm³ = 13556kg/m³

P_{A} = P_{0} +  hρg/ P₀

where, g= acceleration due to gravity, 10m/s²

h= height= 8.6cm = 0.086m

P_{A}= hρg/ P₀

= 0.086 × 13556  × 10

= 11658.16 kgm/ m²s²

= 11658.16 N/m² = 11658.16pa

= 87.4434mmHg

where 1 torr = 1mmHg

P_{0}= 752torr = 752mmHg

P_{A = 752 + 87.4434

= 839.44mmHg

4 0
3 years ago
List of three questions that you are good at science questions.
Klio2033 [76]

Answer:

cycles, graphing, precise measurementation

Explanation:

7 0
3 years ago
Read 2 more answers
Which of the following statements about inertia is true?
Ulleksa [173]

Answer:

D. The inertia of a spaceship on Earth equals the inertia of the spaceship on the moon.

Explanation:

Inertia is the property of mass and it will directly depends on the value of mass of the object

So here inertia of object will change as the mass of the object will change

So here we can say

A. Inertia depends on velocity.

FALSE

As inertia is not a function of velocity

B. Inertia is a measurement of acceleration.

FALSE

it does not depends on acceleration

C. The inertia of a 2 kg bag of flour is greater than the inertia of a 4 kg flower pot.

FALSE

More mass means more inertia so 4 kg must have more inertia

D. The inertia of a spaceship on Earth equals the inertia of the spaceship on the moon.

TRUE

Since mass on Earth and Moon will be same so inertia must be same

4 0
3 years ago
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}

b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
3 years ago
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