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goblinko [34]
3 years ago
12

Baking soda and vinegar can be used as a household drain cleaner, by putting the baking soda powder into the kitchen drain say,

and pouring the vinegar on it. A chemical reaction takes place whereby carbon dioxide is released and removes the clog.
List 3 factors that can affect the rate of reaction of the baking soda and the vinegar, and give reasons for your answer.
Chemistry
2 answers:
Rom4ik [11]3 years ago
8 0
Oxygen co2 nitrogen
Mrac [35]3 years ago
7 0

Answer:

Oxygren co2 and nitrogen

Explanation:

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Carnegie Development stages
Darya [45]

Answer:

Stage 1: 1 days.

Stage 2: 2-3 days.

Stage 3: 4-5 days.

Stage 4: 6 days.

Stage 5 (a-c): 7-12 days.

Stage 6: c. 17 days.

Stage 7: c. 19 days.

Stage 8: c. 23 days.

7 0
3 years ago
PLZZZZ HELP!!!!!! WILL GIVE BRAINLIEST!!
guapka [62]
Color change bubbles and i think dissolving
4 0
4 years ago
Read 2 more answers
Calculate the time needed for a constant current of 0.961 a to deposit 0.500 g of co(ii) as
Vera_Pavlovna [14]

1.70 × 10³ seconds

<h3>Explanation </h3>

\text{Co}^{2+} + 2 e⁻ → \text{Co}

It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.

Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains 0.500 / 58.933 = 8.484\times 10^{-3} \; \text{mol} of Co atoms. It would take 2 \times 8.484 \times 10^{-3} = 0.01697 \; \text{mol} of electrons to reduce cobalt (II) ions and produce the 8.484\times 10^{-3} \; \text{mol} of cobalt atoms.

Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of 1.637 \times 10^{3} \; \text{C}. A current of 0.961 A delivers 0.961 C of charge in one single second. It will take 1.637 \times 10^{3} / 0.961 = 1.70 \times 10^{3} \; \text{s} to transfer all these charge and deposit 0.500 g of Co.

4 0
3 years ago
In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?
IRINA_888 [86]
2 C_{6}H_{6}  +  15O_{2} ----->\ \textgreater \  12CO_{2}  +  6H_{2}O&#10;&#10;&#10;

mol of benzene =  \frac{mass}{Mr}
                                = \frac{10.47g}{(6 * 12) (6 * 1) g/mol}
                                = 0.134 mol

mol of oxygen: 
                 ratio of C_{6} H_{6} :  O_{2}
                 =  2 : 15
                 =  1 : 7.5

: . mol of O_{2} = 0.134mol * 7.5
                                         = 1.01 mol

Mass of Oxygen = mol * Mr
                           = 1.01 mol * (16*2) g/mol
                           = 32.22g 

Note: Mr is molar mass
8 0
3 years ago
What are the similarities and differences for the properties of copper (II) sulphate and copper?
ivann1987 [24]

It is to do with the ionisation of the atom. Copper is a metal, so it will lose electrons. When reacted with a non-metal, it will form an ionic bond.

In copper (I) sulphate, the copper ions have a charge of +1, ie they have lost ONE electron each.

Copper (I) sulphate has the chemical formula Cu2SO4. Each ionic bond involves two Cu+1 ions and a sulphate ion (SO4.

In copper (II) sulphate, the copper ions have a charge of +2, ie they have lost TWO electrons each.

Copper (II) sulphate has the chemical formula CuSO4. Each ionic bond involves a single Cu+2 ion and a sulphate ion (SO4).

So, really, it’s down to the chemical structure and the ionisation of the atom. Apart from the chemistry, copper (I) sulphate a very obscure chemical. Although, after a bit of googling, I have managed to find some info and vendors, it appears that this chemical is rarely seen and doesn’t have many practical uses.

Copper (II) sulphate, on the other hand, is incredibly common. It’s in every school chemistry lab. If someone says “copper sulphate” they will be talking about this chemical, not copper (I) sulphate. In pure form, it is a boring white powder, but when hydrated, it takes on it’s better known blue colour, with blue crystals and blue solution.

Hope this helps.

3 0
3 years ago
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