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REY [17]
3 years ago
12

the relationship between period and frequency is represented by the following equation: frequency = 1/period or period = 1/frequ

ency true or false
Physics
2 answers:
ivanzaharov [21]3 years ago
7 0
<span>True</span>

Frequency, f = 1/Period,T            or   Period, T =  1/Frequency, f




Hunter-Best [27]3 years ago
5 0

Answer:

<h2>True.</h2>

Explanation:

Frequency and Period are inverse magnitudes. They are complete opposite because <em>Period is defined as the amount of laps can be given in a second; and Frequency is how many seconds are used to complete a lap.</em>

This magnitudes are studied in Rotational Movement in Physics.

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The human heart is an organ that pumps blood throughout the body via the circulatory system, supplying oxygen and nutrients to the tissues and removing carbon dioxide and other wastes.

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About how much of the United States' electricity is produced by nuclear reactors?​
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19% total electrical output

Explanation:

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Political scientists use political models to describe which of the following? a. political spectrum b. political shift c. politi
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D

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12. An organ pipe that is 1.75 m long and open at both ends produces sound of
podryga [215]

Answer:

354 m/s

Explanation:

For the second overtune (Third harmonic) of an open pipe,

λ = 2L/3................................ Equation 1

Where L = Length of the open pipe, λ = Wave length.

Given: L = 1.75 m.

Substitute into equation 1

λ = 2(1.75)/3

λ = 1.17 m.

From the question,

V = λf.......................... Equation 2

V = speed of sound in the room, f = frequency

Given: f = 303 Hz.

Substitute into equation 2

V = 1.17(303)

V = 353.5

V ≈ 354 m/s

Hence the right answer is 354 m/s

8 0
3 years ago
A man paddles a canoe at 6 km per hour. If he paddles on a river with a current of 6 km per hour, what is the speed of the canoe
Romashka-Z-Leto [24]

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]

5 0
3 years ago
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