Question 3 (0.4 points)

According to Newton’s law of universal gravitation, as we move to higher altitudes, the force of gravity on us decreases and as we gain mass, the force of gravity on us increases both are the true statement.

Explanation:

Newton law of universal gravity extends gravity beyond the earth's surface. This gravity depends on the masses directly and inverse to the distance square between their centers.

$F=G \frac{M \times m}{r^{2}}$

Where,

F – Force, G – gravitational constant, M and m – masses in kg, r – distance in meters.

Since force is proportional to the masses of interacting objects. If the mass of any one object increases, gravity between them also gets increased. When moving to higher altitude, force decreases as the distance is inverse proportion to gravity.

4 0

3 years ago

Read 2 more answers

I need help on (a) I don't know what equation to use?

Alchen [17]

Impulse = (force) x (length of time the force lasts)

I see where you doodled (60)(40) over on the side, and you'll be delighted
to know that you're on the right track !

Here's the mind-blower, which I'll bet you never thought of:
On a force-time graph, impulse (also change in momentum)
is just the area that's added under the graph during some time !

From zero to 60, the impulse is just the area of that right triangle
under the graph. The base of the triangle is 60 seconds. The
height of the triangle is 40N . The area of the triangle is not
the whole (base x height), but only 1/2 (base x height).

1/2 (base x height) = 1/2 (60s x 40N) = 1,200 newton-seconds

That's the impulse during the first 60 seconds. It's also the change in
the car's momentum during the first 60 seconds.

Momentum = (mass) x (speed)

If the car wasn't moving at all when the graph began, then its momentum is 1,200 newton-sec after 60 seconds. Through the convenience of the SI system of units, 1,200 newton-sec is exactly the same thing as 1,200 kg-m/s . The car's mass is 3 kg, so after 60 sec, you can write

Momentum = M x V = (3 kg) x (speed) = 1,200 kg-m/s

and the car's speed falls right out of that.

From 60to 120 sec, the change in momentum is the added area of that
extra right triangle on top ... it's 60sec wide and only 20N high. Calculate
its area, that's the additional impulse in the 2nd minute, which is also the
increase in momentum, and that'll give you the change in speed.

8 0

3 years ago

A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work

yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

Mass of car; $m = 200kg$

Acceleration of the car; $a = 0.5m/s^2$

Distance covered by the car; $d = 10m$

Work done; $W = \ ?$

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

$Work\ done = f * d$