Given:
The given value is 
.
To find:
The value of the given expression by using the Binomial approximation.
Explanation:
We have,
It can be written as:
![[\because (1+x)^n=1+nx]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%281%2Bx%29%5En%3D1%2Bnx%5D)
Therefore, the approximate value of the given expression is 1.0002.
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
Sound source is at rest, you are moving with velocity v, f = frequency, c = speed of sound:
f = f0(1 + v/c)
115 = 100(1 + v/343)
115 = 100 + 100v/343
15 = 100v/343
v = 15*343/100
<span>
v = 51,45 m/s </span>
Answer:
1.2 amps :)
Explanation:
A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?
Known:
Unknown:
I = V/R
= 12.0 V / 10.0 Ω
= 1.2 amps
Answer: Relative motion
Explanation: If two objects are moving either towards or away from each other with both having their velocities in a reference frame and someone is outside this reference frame seeing the motion of the two objects.
The observer ( in his own frame of reference) will measure a different velocity as opposed to the velocities of the two object in their own reference frame. p
Both the velocity measured by the observer in his own reference frame and the velocity of both object in their reference is correct.
Velocities of this nature that have varying values based on motion referenced to another body is known as relative velocity.
Motion of this nature is known as relative motion.
<em>Note that the word reference frame is simply any where the motion is occurring and the specified laws of motion is valid</em>
<em />
For this example of ours, the reference frame of the companion is the train and the telephone poles has their reference frame as the earth.
The companion will measure the velocity of the telephone poles relative to him and the velocity of the telephone pole relative to an observer outside the train will be of a different value.
