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Law Incorporation [45]
3 years ago
5

Which of the following is a reason to express scientific findings mathematically? A. The findings become more difficult to prove

by experiment. B. The findings become easier to verify by experiment. C. The findings become more confusing. D. The findings become less appealing to the public.
Physics
1 answer:
mafiozo [28]3 years ago
5 0
Now really ! 

If there were some kind of treatment of the results that made them
more difficult to prove by experiment, or made them more confusing,
or made them less appealing to the public, then there would be no
reason on Earth to treat them that way. 

Choice ' B ' is the only positive effect, so it's the only reason you'd
WANT to handle your findings that way.
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Car sitting on a drive way is that an kinetic or potential energy​
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Answer:

kinetic energy..........

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3 years ago
A certain sound is recorded by a microphone. The same microphone then detects a second sound, which is identical to the first on
olya-2409 [2.1K]

Answer:

It is perceived as louder.

Explanation:

Amplitude affects the loudness of sound.

Frequency and wavelength affect the pitch of the sound.

3 0
3 years ago
The box shown on the rough ramp above is sliding up the ramp.calculate the force of friction on the box
Anna [14]

We are given a box that slides up a ramp. To determine the force of friction we will use the following relationship:

F_f=\mu N

Where.

\begin{gathered} N=\text{ normal force} \\ \mu=\text{ coefficient of friction} \end{gathered}

To determine the Normal force we will add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction as shown in the following diagram:

In the diagram we have:

\begin{gathered} m=\text{ mass}_{} \\ g=\text{ acceleration of gravity} \\ mg=\text{ weight} \\ mg_y=y-\text{component of the weight. } \end{gathered}

Adding the forces in the y-direction we get:

\Sigma F_y=N-mg_y

Since there is no movement in the y-direction the sum of forces must be equal to zero:

N-mg_y=0

Now we solve for the normal force:

N=mg_y

To determine the y-component of the weight we will use the trigonometric function cosine:

\cos 40=\frac{mg_y}{mg}

Now we multiply both sides by "mg":

mg\cos 40=mg_y

Now we substitute this value in the expression for the normal force:

N=mg\cos 40

Now we substitute this in the expression for the friction force:

F_f=\mu mg\cos 40

Now we substitute the given values:

F_f=(0.2)(10\operatorname{kg})(9.8\frac{m}{s^2})\cos 40

Solving the operations:

F_f=15.01N

Therefore, the force of friction is 15.01 Newtons.

3 0
1 year ago
Two manned satellites approaching one another at a relative speed of 0.550 m/s intend to dock. The first has a mass of 2.50 ✕ 10
NNADVOKAT [17]

Answer: Their final relative velocity is -0.412 m/s.

Explanation:

According to the law of conservation,

      m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v

Putting the given values into the above formula as follows.

      m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v

     2.50 \times 10^{3} kg \times 0 m/s + 7.50 \times 10^{3} kg \times -0.550 m/s = (2.50 \times 10^{3} kg + 7.50 \times 10^{3} kg)v

           -4.12 \times 10^{3} kg m/s = (10^{4} kg) v

                   v = \frac{-4.12 \times 10^{3} kg m/s}{10^{4} kg}

                      = -0.412 m/s

Thus, we can conclude that their final relative velocity is -0.412 m/s.

8 0
4 years ago
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. how long does h
noname [10]
The shot putter should get out of the way before the ball returns to the launch position.

Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.

The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 =  0.45 s

t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.

Answer: 0.45 s
7 0
3 years ago
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