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Law Incorporation [45]
4 years ago
5

Which of the following is a reason to express scientific findings mathematically? A. The findings become more difficult to prove

by experiment. B. The findings become easier to verify by experiment. C. The findings become more confusing. D. The findings become less appealing to the public.
Physics
1 answer:
mafiozo [28]4 years ago
5 0
Now really ! 

If there were some kind of treatment of the results that made them
more difficult to prove by experiment, or made them more confusing,
or made them less appealing to the public, then there would be no
reason on Earth to treat them that way. 

Choice ' B ' is the only positive effect, so it's the only reason you'd
WANT to handle your findings that way.
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Three resistors of equal resistance are connected in series as shown. Compared to the voltage provided by the battery, voltage a
dsp73

Answer:

the voltage across each resistor is one third of the battery voltage

Explanation:

In a series circuit, the current is constant throughout the circuit, so the battery voltage is equal to the sum of the voltage drop in each part of the series circuit.

        V = i (R₁ + R₂ + R₃)

       

in the exercise indicate that all resistance has the same value

         R₀ = R₁ = R₂ = R₃

        V = i 3 R₀

        V = 3 V₀

         V₀ = i R₀

          V₀= V / 3

the voltage across each resistor is one third of the battery voltage

6 0
3 years ago
A stone is thrown vertically upward with a speed of 28.0 m/s how much time is required to reach this height
Solnce55 [7]
A stone is thrown vertically upward with a speed of 17.0 m/s. How fast is it moving when it reaches a height of 11.0 m? How long is required to reach this height?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 17.0m/s, a = -g = -9.81m/s^2, s = 11.0m and we want to know v and t, so from equation (2):

v^2 = u^2 + 2as

v^2 = 17.0^2 -2(9.81)(11.0)

v = √73.18 = 8.55m/s

now from equation (3):

v = u + at

8.55 = 17.0 – 9.81t

t = (8.55 – 17.0)/(-9.81) = 0.86s
6 0
3 years ago
a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed
Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

\Delta x \Delta p\geq \frac{h}{4\pi}      (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}

The minimum kinetic energy is calculated by using the following formula:

k=\frac{(\Delta p)^2}{2m}       (2)

m: mass of the proton = 1.67*10^{-27}kg

k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J

in eV you have:

2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV

The kinetic energy of the proton is 1.29eV

7 0
3 years ago
The mass of the sun is 2*10^30 kg and its radius is
Marta_Voda [28]

Explanation:

Distance d=1.5×108 km=1.5×1011 m

Mass of the sun, m=2×1030 kg

Mass of the earth, M=6×1024 kg

Force of gravitation, F=G×d2m×M

F=6.7×10−11×(1.5×1011)22×1030×6×1024=3.57×1022 N

4 0
3 years ago
g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the oth
MrMuchimi

Answer:

B_{net} =(2\times 10^{-5}T/A).(I-25A)

Explanation:

Given :

the distance between the two wires is  = 2 cm

                                                                  = 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

B_{net} = \frac{\mu _{o}\times I_{1}}{2\pi r_{1}}-\frac{\mu _{o}\times I_{2}}{2\pi r_{2}}

                            =\frac{(4\pi \times 10^{-7}T.m/A)}{2\pi (1\times 10^{-2}m)}\times (I-25A)

                            = (2\times 10^{-5}T/A).(I-25A)

4 0
3 years ago
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