Answer:
the voltage across each resistor is one third of the battery voltage
Explanation:
In a series circuit, the current is constant throughout the circuit, so the battery voltage is equal to the sum of the voltage drop in each part of the series circuit.
V = i (R₁ + R₂ + R₃)
in the exercise indicate that all resistance has the same value
R₀ = R₁ = R₂ = R₃
V = i 3 R₀
V
= 3 V₀
V₀ = i R₀
V₀= V / 3
the voltage across each resistor is one third of the battery voltage
A stone is thrown vertically upward with a speed of 17.0 m/s. How fast is it moving when it reaches a height of 11.0 m? How long is required to reach this height?
Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):
s = ut + ½ at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we know u = 17.0m/s, a = -g = -9.81m/s^2, s = 11.0m and we want to know v and t, so from equation (2):
v^2 = u^2 + 2as
v^2 = 17.0^2 -2(9.81)(11.0)
v = √73.18 = 8.55m/s
now from equation (3):
v = u + at
8.55 = 17.0 – 9.81t
t = (8.55 – 17.0)/(-9.81) = 0.86s
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):

The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg

in eV you have:

The kinetic energy of the proton is 1.29eV
Explanation:
Distance d=1.5×108 km=1.5×1011 m
Mass of the sun, m=2×1030 kg
Mass of the earth, M=6×1024 kg
Force of gravitation, F=G×d2m×M
F=6.7×10−11×(1.5×1011)22×1030×6×1024=3.57×1022 N
Answer:
=
Explanation:
Given :
the distance between the two wires is = 2 cm
= 0.02 m
Current in one of the wire, I = 25 A
Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.
Therefore we know that
= 
=
= 