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dmitriy555 [2]
4 years ago
5

Can someone explain what streamlining is in a simple way with an example.

Physics
1 answer:
Usimov [2.4K]4 years ago
6 0
Imagine a car, and imagine you see little arrows below and beneath it, just around it. <span>The path of a particle that is flowing steadily and without turbulence in a fluid past an object.</span>
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The natural pH of rain water is?
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5.6 which would be acidic!
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Which of the following best explains why clear-cutting forests is more destructive than selectively cutting down trees in forest
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The instrument used to measure the diameter of a thin wire is​
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The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths.less for long wavelengths a
kompoz [17]
<h2>Answer: The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths</h2>

Here we are talking about Diffraction and, in fact, waves diffract the most when their wavelength is about the same size of the gap or aperture.

Diffraction happens when a wave (mechanical or electromagnetic wave) meets an obstacle or a slit .When this occurs, <u>the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit. </u>

<u />

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.

This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.

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3 years ago
PLEASE HELP ME ON THIS ONE ANYONE
andreev551 [17]

Answer:

A & B

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A & B Would be the right answer since Morse code cannot be represented through the height of the fire.

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