Assume that the small-massed particle is
and the heavier mass particle is
.
Now, by momentum conservation and energy conservation:


Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

So now, we see that
and
. So therefore, the smaller mass recoils out.
Hope this helps you!
Bye!
The answer is C. An occluded front.
Answer: The work done in J is 324
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:

W = amount of work done = ?
P = pressure = 732 torr = 0.96 atm (760torr =1atm)
= initial volume = 5.68 L
= final volume = 2.35 L
Putting values in above equation, we get:

To convert this into joules, we use the conversion factor:

So, 
The positive sign indicates the work is done on the system
Hence, the work done for the given process is 324 J
In the beginning, the melting stage they call it.