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Korvikt [17]
3 years ago
12

Write the molecular formula for the compound that exhibits a molecular ion at M+ = 112.0499. Assume that C, H, N, and O might be

present, and use the exact masses below:
Exact mass of carbon = 12.000
Exact mass of hydrogen = 1.0078
Exact mass of nitrogen = 14.003
Exact mass of oxygen = 15.995

The order of atoms should be carbon, then hydrogen, then the others in alphabetical order.
Chemistry
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

C₆H₁₀NO

Explanation:

In order to arrive at a molecular formula we have to make some assumptions and they are

Assuming there is one ( 1 ) N and one ( 1 ) O that is present in the said molecule

Total mass =   29.998

next step: subtract the total mass from 112.0499 = 82.501

next : assume the presence of 6 carbon atoms in said molecule

Total mass =  6 * 12 = 72

Mass of Hydrogens = 82.501 - 72 = 10.501

∴ number of hydrogens = 10.501 / 1.0078  ≈ 10

Hence Total mass = 29.998 + 82.501  ≈ 112.0499

Finally Molecular formula = C₆H₁₀NO

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To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

<h3>What is Mole concept ?</h3>

A mole is a unit of measurement used to measure the amount of any fundamental entity (atoms, molecules, ions) present in the substance.

As according to the given equation, 2 moles (ie 12.04 x 10²³ atoms) of Na-atoms produces 1 mole (22.4 ltr) of H₂-gas.

Hence, to produce 33.6 ltr (equivalent to 33.6 dm³) of H₂-gas produced by ;

   = 12.04 x 10²³ atoms of Na / 22.4 ltr of H₂-gas x 33.6 ltr

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Hence, To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

Learn more about Mole concept here ;

brainly.com/question/20483253

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