Answer:The formula for kinetic energy is
(1/2) M V^2.
With M in kg and V in m/s, the answer will be in Joules.
K.E = 40joule
Explanation:
Given the speed of the sound in the problem which is 1 mile per 5 seconds.
The speed is calculated by:
Speed = distance/time = (1mi/5s) (1610 m/1mi) = 300 m/s
Note that only 1 significant figure is given which is 5 second and so only 1 significant figure is justified in the result. The speed of sound is 343 m/s. therefore the rule of thumb is fairly close.
The charge transported as a result of charging is 43200C .
we can note the following data from the statement :
Current (i) = 3A
Time interval (t) = 4 hrs = 14400secs
As we know ,
Current is defined as the rate of flow of the charges between two points when a potential difference is applied between them.
Mathematically , it can be written as
Current(i) = charge (q)/ time(t)
Q = i × t
= 3 × 14400
= 43200 C
By dividing the value of the current passed through the circuit by the time for which the charge is passed gives out the value of the charge passed .
learn more on charges :
brainly.com/question/15238352
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Based on the changes in the light curve and the behavior of the series of spectra, this is a<u> binary system. </u>
<h3>How is this is binary system?</h3>
The characteristics described are those of a binary system with the specific type of system being the spectroscopic binary system.
This is because in a spectroscopic binary system, there won't be significant changes in brightness but as a result of stars orbiting towards and then away from us, spectral features will appear as alternative absorption lines.
In conclusion, this is a binary system.
Find out more on binary systems at brainly.com/question/15868824.
Answer:
m1 = 20g (= 0.02 kg)
Mass of pistol, m2 = 2 kg
Initial velocity of the bullet (u1) and pistol (u2) = 0
Final velocity of the bullet, v1 = +150m s-1
Let v be the recoil velocity of the pistol.
Total momentum of the pistol and bullet after it is fired is
= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)
= (3 + 2v) kg m s-1
Total momentum after the fire = Total momentum before the fire
3 + 2v = 0
→v = -1.5 m/s
