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Cerrena [4.2K]
3 years ago
10

Which statement is true? A) The work done to lift an object 6 meters is greater than the gravitational potential energy it gains

. B) The work required to push an object is less than the work required to pull an object the same distance. C) The work required to raise an object to a height is equal to the gravitational potential energy the object gains. D) The work done against gravity to lift an object straight up is greater than the work required to roll it up a ramp.
Physics
1 answer:
inna [77]3 years ago
4 0

The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>

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A project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow fo
Ksju [112]

Answer:

A. The project's energy costs will decrease

Explanation:

Since the project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow for on-site renewable energy.

Hence, the project's energy costs will decrease very well because it's implementing both of these strategies;

- Area with demand-response program.

- On-site renewable energy.

5 0
3 years ago
The force produced by gravity on a mass is called
Yakvenalex [24]

Answer:

gravitational force

weight

Explanation:

5 0
3 years ago
Newton's Law of Gravitation states that two bodies with masses m1 and m2 attract each other with a force F, where r is the dista
Marrrta [24]

Answer:

W = - 5.01 10¹⁰ J

Explanation:

Work is defined by the expression

      W = ∫ F.dr

Where the blacks indicate vectors, in the case the force is radial and the distance is also radial, whereby the scalar producer is reduced to an ordinary product

      W = ∫ F dr

      W = G m₁m₂ ∫ 1 /r² dr

     W = G m₁ m₂2(-1 / r)

We evaluate between the lower limits r = Re and upper r = ∞

     W = G m₁m₂ (-1 / Re + 1 / ∞)

     W = - G m₁ m₂ / Re

Let's calculate

    W = - 6.67 10⁻¹¹ 800 5.98 10²⁴ / 6.37 10⁶

    W = - 5.01 10¹⁰ J

4 0
3 years ago
A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery a
Inessa [10]

Answer:

The potential difference between the plates increases

Explanation:

As we know that the capacitance of the capacitor is given by:

q = CV         (1)

where

q = charge

C = capacitance

V = Voltage or Potential Difference

Also, the capacitance of a parallel plate capacitor is given as:

C = \frac{\epsilon_{o}A}{D}           (2)

where

\epsilon_{o} = permittivity of free space or vacuum

A = Area of the plates

D = Separation distance between the plates

Now, from eqn (1) and (2):

V = \frac{qD}{A\epsilon_{o}}

Now, from the above eqn  we can say that:

Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.

Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.

4 0
3 years ago
Longitudinal waves cannot travel through a vacuum. True False
JulsSmile [24]
FALSE <span>Only electromagnetic </span>waves<span> can </span>travel through a vacuum<span>; mechanical </span>waves<span> such as sound </span>waves<span> require a particle-interaction to transport their energy. There are no particles in a </span>vacuum<span>. </span>Waves<span> are either </span>longitudinal<span> or transverse.
</span>Hoped i helped   :):)
4 0
3 years ago
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