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Cerrena [4.2K]
3 years ago
10

Which statement is true? A) The work done to lift an object 6 meters is greater than the gravitational potential energy it gains

. B) The work required to push an object is less than the work required to pull an object the same distance. C) The work required to raise an object to a height is equal to the gravitational potential energy the object gains. D) The work done against gravity to lift an object straight up is greater than the work required to roll it up a ramp.
Physics
1 answer:
inna [77]3 years ago
4 0

The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>

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T-Joe (65 kg) is running at 3 m/s. T-Brud (50 kg) is running at 4 m/s. What would be T-Joe's momentum?
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Answer:

P_J=195N

Explanation:

From the question we are told that

Mass\ of T-joe\ M_J=65\\Velocity\ of T-joe\ V_J=3m/s\\Mass of\ T-Brud\ M_B=50kg\\Velocity\ of T-Brud\ V_B=3m/s\\

Generally the equation for momentum is mathematically given by

P=mv

Therefore

T-Joe momentum P_J

P_J=65*3

P_J=195N

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2 years ago
how much energy must be transferred to a normal incandescent bulb (efficiency 0.05) for it to transfer 9J of energy by light?
oksian1 [2.3K]

Answer:

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Explanation:

3 0
3 years ago
Trey races his bicycle for 192m. A wheel of his bicycle turns 48 times as the bicycle travels this distance. What is the diamete
chubhunter [2.5K]

Answer:

1.27 m

Explanation:

Distance = 192 m

number of rotations = 48

Distance traveled in one rotation = 2 x π x r

Where, r be the radius of wheel.

so, distance traveled in 48 rotations = 48 x 2 x 3.14 x r

It is equal to the distance traveled.

192 = 48 x 2 x 3.14 x r

r = 0.637 m

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7 0
2 years ago
Read 2 more answers
You are testing a new amusement park roller coaster with an empty car with a mass 120 kg. One part of the track is a vertical lo
Kay [80]

Answer:

- 5436 J

Explanation:

mass of car, m = 120 kg

radius of loop, r = 12 m

velocity at the bottom (A) = Va = 25 m/s

Velocity at the top(B) = Vb = 8 m/s

Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m

by use of Work energy theorem

Work done by all the forces = change in kinetic energy of the body

Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A

- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)

- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)

- 28224 + Work done by friction = - 33660

Work done by friction = -33660 + 28224 = - 5436 J

4 0
3 years ago
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