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4 years ago

Looking for some help with the left side of the table and the questions followed :)

Physics

1 answer:

Inessa [10]4 years ago

6 0

Answer:

(1). Going in the order: Gas, Liquid, Solid.

Particle separation: Very large; large; small.

Strength of forces between particles: very weak; weak; strong.

(2). a. The change of state is condensation.

b. The density of the substance is increasing as particles move closer together.

(3). a. The liquid's temperature decreases until it reaches solidification (freezing) point, and then the temperature will remain constant until all of the liquid has solidified.

b. The particles move with less and less energy until they have low enough energy to come together and solidify, then they will release more energy when they come together to form bonds, and vibrate about their equilibrium positions once they are part of a molecular bond.

Additional explanation:

(1). The particle separation in a gas is very large because the gas has a very low density, and since particles are not that close together,<em> the strength of forces between particles is very weak</em>.

The liquid is somewhat more denser than the gas and therefore the particle separation is large but less than that in a gas,<em> The strength of forces between particles is still weak but greater than in a gas. </em>

Finally, particle separation in a solid is small because the solid is still more denser than the liquid, and the strength of forces between particles is strong because it's these forces that give a solid its rigid shape.

(2). a.The change of state of a substance in which particles slow down and move close together is called condensation.

b. As the particles move close together, they are occupying less and less volume; therefore, the density is increasing.

(3). The explanation is already given in the answer.

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Suppose that the design parameters of the satellite's control system require that the angular velocity of the satellite not exce

Stells [14]

Answer:

v=0.04m/s

Explanation:

To solve this problem we have to take into account the expression

$\omega=\frac{v}{r}$

where v and r are the magnitudes of the velocity and position vectors.

By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that

$|r|=\sqrt{(-1.18m)^2+(-0.9m)^2}=2.01m\\\\v=\omega r=(0.02\frac{rad}{s})(2.01m)=0.04\frac{m}{s}$

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hope this helps!!

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3 years ago

Read 2 more answers

What type of change has an appearance change but the substance does not change?

katovenus [111]

Answer:

Physical change is what doesn't have a substance change

Explanation:

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3 years ago

A magician quickly pulls on a tablecloth and the items remain in place.Why does this happen

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Newton's first law says that the tableware will remain motionless unless acted upon by an outside force.

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3 years ago

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

tresset_1 [31]

Answer:

Explanation:

a. Given that:

$m-$ mass of first & second piece, $3m-$ mass of 3rd piece, $\bar v_1$ -velocity of first piece( $-23\dot i \ m/s$ ) and $\bar v_2$ as velocity of 2nd piece ( $-23\dot j \ m/s$ )

Let $\bar v_3$ be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

$m\bar v_1 +m\bar v_2 +3m \bar v_3=0$ #Dividing both sides by $m, m\neq 0$

$\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)$

#Plug the $\bar v_1 ,\bar v_2$ values:

$\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)$

#So the magnitude of the third piece is:

$|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s$

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the $x$ -axis), we find $\angle \theta$ . The angle is obtained by getting the tan inverse as: