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2 years ago

Gail has 8 coins. their total value is 93 cents. what coins does she have?

Mathematics

2 answers:

Vlada [557]2 years ago

6 0

9 dimes and 3 pennies

alexira [117]2 years ago

5 0

3 quarters_75 cents

1 nickel_5 cents

1 dimes_10 cents

3 pennies _3 cents

75+5+10+3=93 cents

3+3+1+1=8 coins

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The population of a town is 2100 and increasing at a rate of 1.3% per year, while the number of cats in the town is currently 10

stich3 [128]

Answer:

when # cats exceeds 2,313

Step-by-step explanation:

if you graph y = .013x + 2100 and y = .08 + 1000 you will see the lines intersect when the town population is 16,418 and the number of cats equals 2,313.

6 0

2 years ago

The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 73.7 m

umka2103 [35]

Answer:

a) 0.2347, 0.0007

b) 1.30

c) 0.63

Step-by-step explanation:

Given –

Mean = 73.4

Sigma = 4.7

Probability that the speed is greater than 70 is

P (X>70) = P (z> (70-73.4)/4.7) = P (z>-0.72) = 0.7653

a) The probability that a car is not speeding = 1 - 0.7653 = 0.2347

The probability that all 5 cars are not speeding = (0.2347)5 = 0.0007

b) E (X) = 1/p = 1/0.7653 = 1.30

c) Standard deviation = Sqrt (1-p/p) = (1-0.7653)/0.7653 = 0.63

5 0

2 years ago

Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

choli [55]

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(4-0)^2+(1-4)^2}$

$AB=\sqrt{(4)^2+(-3)^2}$

$AB=\sqrt{16+9}$

$AB=\sqrt{25}$

$AB=5$

Similarly,

$BC=\sqrt{(1-4)^2+(-3-1)^2}$

$BC=5$

$CD=\sqrt{(-3-1)^2+(0-(-3))^2}$

$CD=5$

And,

$AD=\sqrt{(-3-0)^2+(0-4)^2}$

$AD=5$

Now, the perimeter of the quadrilateral ABCD is:

$P=AB+BC+CD+AD$

$P=5+5+5+5$

$P=20$

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

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2 years ago

A box 4 cm by 6 cm by 8 cm is painted on all six faces and then cut into cubes with the 2 cm sides. How many of these cubes have

Vera_Pavlovna [14]

Answer:

4 Cubes

Step-by-step explanation:

A box 4 cm by 6 cm by 8 cm is painted on all six faces.

The volume of the box = L × B × W

V = 4 × 6 × 8 = 192 cm³

The box cut into cubes with the 2 cm sides.

Volume of the 2 cm cube = 2 × 2 × 2 = 8 cm³

The number of cubes from the box = $\frac{192}{8}$

= 24 cubes

There would be 4 cubes in the middle would be painted only one side.

Periphery cubes of the box are painted on two or more sides.

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2 years ago

How do you solve a perfect square trinomial??

Nuetrik [128]

Answer:

Step-by-step explanation:

Here's an example:

x^2 + 6x + 9 = 0

First factorise it:

(x + 3)(x + 3) = 0

So the solution is x = -3 (multiplicity 2)

That is there are 2 roots both -3.

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1 year ago