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4 years ago

SOLVE FOR “V” gh=(1/2)(v^2) PLEASE AND THANK YOU!

Physics

1 answer:

Alchen [17]4 years ago

5 0

Answer:

square root of 2gh

Explanation:

gh=(1/2)(v^2)

dividing both sides by 1/2, we have

2gh=v^2

therefore;

v=square root of 2gh

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Sarah and Maisie are analysing data from their school sports day. Looking at the 1500 m results for Stephen, Maisie believes tha

Dahasolnce [82]

Answer:

Sarah is right

Explanation:

This is an exercise that differentiates between scalars and vectors.

A scalar is a number, instead a vector is a number that represents the module in addition to direction and sense.

In this case, the distance (scalar) traveled is a number, which is why it is worth 1500m, but the displacement is a vector and since the point where it leaves is the same point where the vector's modulus arrives is zero, so the DISPLACEMENT VECTOR is zero

consequently Sarah is right

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3 years ago

A man jumps horizontally from the top of a building that is 20.0m high, and hopes to reach a swimming pool that is at the bottom

Oliga [24]

Answer:

5 m/s

Explanation:

Given that the hight of the building, h= 20.0 m

The horizontal distance of the swimming pool from the building, d=10 m

As the man jumps horizontally, so the vertical velocity at the time of jumping is 0.

Let s be the initial horizontal velocity of the man at the time of jumping.

As the gravitational force always acts in the vertical direction, so, it does not change the horizontal speed.

So, the horizontal velocity, s, remains constant throughout the motion.

If t be the time of flight, then $s=10/t \cdots(i)$

Now, applying the equation of motion in the vertical direction,

$s=ut+\frac 1 2 at^2$

where u is the initial velocity, t is the time of flight, a is the acceleration, s is the displacement.

Here, putting s= 20 m, u=0, $a=g=9.81 m/s^2$ in the equation of motion, we have

$20=0\timest+\frac 1 2 (9.81)t^2 \\\\\Rightarrow 20 = \frac 1 2 (9.81)t^2 \\\\\Rightarrow t^2 = (20\times2)/9.81 \\\\$

$\Rightarrow t = 2$ seconds (approx)

Now, put t=2 in the equation ( we have

$s=10/2=5$ m/s

Hence, the man must jump with 5 m/s horizontally to reach the pool.

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3 years ago

What is astrometry? What is astrometry? measuring the positions of stars on the sky using metric units for distance (e.g. meters

Fofino [41]

Explanation:

It is a branch of astronomy wherein measurements of the positions and movements of celestial bodies are precisely are made.

For the measurement, minute wobbling of the position of the body is detected. When the shift is detected periodically, the astronomers come to know that the star is orbited by a planet.

Also, basic data about the properties of the stars can be collected using this method.

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3 years ago

The farther a star is away from earth, the more it is

Darya [45]

The more it is Red shifted.

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4 years ago

Read 2 more answers

Does a star's apparent brightness depend only on its distance from earth?

Arisa [49]

I dont think so. It also probably matters what type of str it is