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2 years ago

9

What is the speed of light?

2 answers:

amm18122 years ago

3 0

<span>299 792 458 m / s hop i helped</span>

aleksandrvk [35]2 years ago

3 0

Something that moves faster than a light turning on. or 299 792 458 m / s and as the person put above in the coments

"<span>The speed of light in vacuum, commonly denoted c, is a universal physical constant important in many areas of physics. Its precise value is 299792458 metres per second (approximately 3.00×10⁸ m/s), since the length of the metre is defined from this constant and the international standard for time"
so give a tnx to </span>whosfrostyy

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A metal bar moves through a magnetic field. the induced charges on the bar are

Dmitry [639]

I would say its a positive cgarge

7 0

3 years ago

1.A body of certain mass is kept at a height of 15m from the ground, taking the value of g as 10m/s find out the mass of the bod

ehidna [41]

Answer:

1.#potential energy = PE, m = mass in kg, g = force of gravity, h= vertical height above the ground. ** means to the power of ie exponent. * means multiply.

PE = mgh

300 = m(10)(15)

m = 300/(10)(15)

m= 2kg

2. KE = 1/2 mv**2

= 1/2(50)(50)**2

= 2500 joules

Explanation

Is as in solution

4 0

2 years ago

Identify the conditions for an elastic collision in a closed system. Check all that apply.

s344n2d4d5 [400]

Answer:

In an elastic collision:

There is no external net force acting. Thus, Momentum before and after collision is equal. Momentum remains conserved.

Total energy always remains conserved as energy cannot be created nor destroyed. It can change from one form to another.

There is no lost due to friction in elastic collision. So the kinetic energy is also conserved.

Velocities may change after collision. If the masses are equal, the velocities interchange.

When one object is stationary:

Final velocity of object 1:

v₁ = (m₁ - m₂)u₁/(m₁ +m₂)

Final velocity of object 2:

v₂ = (2 m₁ u₁)/(m₁+m₂) =

Objects do not stick together in elastic collision. They stick together in inelastic collision.

One object may be stationary before the elastic collision.

Thus, conditions for an elastic collision:

Energy is conserved.
Velocities may change.
Momentum is conserved.
Kinetic energy is conserved.
One object may be stationary before the elastic collision.

7 0

2 years ago

Read 2 more answers

(r= -82) is a example of what correlation

coldgirl [10]

Answer:

the linear dependence between two variables

6 0

2 years ago

What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?

Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

$I=\dfrac{E^2}{2\mu_{0}c}$

$E=\sqrt{2\times I\mu_{0}c}$

Put the value into the formula

$E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}$

$E=931.17\ N/C$

Using formula of magnetic field

$B = \dfrac{E}{c}$

Put the value into the formula

$B=\dfrac{931.17}{3\times10^{8}}$

$B=0.0000031039\ T$

$B=3.10\times10^{-6}\ T$

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

$F=\dfrac{Gm_{s}M_{e}}{r^2}$

Put the value into the formula

$F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}$

$F=3.522\times10^{22}\ N$

We need to calculate the radiation force

Using formula of force

$F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}$

Put the value into the formula

$F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2$

$F_{R}=4.8\times10^{8}\ N$

The gravitational and solar electromagnetic pressure forces of the sun on the earth

$\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}$

$\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}$

Hence, This is the required solution.

3 0

3 years ago