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3 years ago

Does a star's apparent brightness depend only on its distance from earth?

2 answers:

5 0

<span>The luminosity of a star, on the other hand, is the amount of light it emits
from its surface..... However, apparent brightness is not an intrinsic property of
the star; it depends on your location</span>

Arisa [49]3 years ago

4 0

I dont think so. It also probably matters what type of str it is

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Comparing Wave A (black) to Wave B (green), Wave A has a

Gennadij [26K]

I think it's C, longer wave length.

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4 years ago

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A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that

motikmotik

Answer:

B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.

C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.

E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.

#FreeMelvin

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4 years ago

A ball falls from the top of a building. As it falls, its speed increases. Which type of energy is the ball gaining as it falls?

Elina [12.6K]

<h2>Hello!</h2>

The answer is: B. Kinetic energy

Since the ball is falling, speed increases because the gravity acceleration is acting. When speed increases, the kinetic energy increases too, so the ball is gaining kinetic energy.

The gravity acceleration is equal to $9.81\frac{m}{s^{2}}$ , it means that when falling, the ball will increase it's speed 9.81m every second.

We can calculate the kinetic energy by using the following formula:

$KE=\frac{1}{2}*m*v^{2}$

Where:

$m=mass\\v=velocity$

Have a nice day!

<h2 />

5 0

4 years ago

Find an equation relating the rate of change of kinetic energy to the rate of change of velocity

alexdok [17]

Answer:

djjdjfjfntjfjjfjxuxidie

Explanation:

hjdjfjjfjf urfjfjfuuijjjjjjjjjkjsjjsj

4 0

3 years ago

Experiments using "optical tweezers" measure the elasticity of individual DNA molecules. For small enough changes in length, the

GalinKa [24]

Answer:

Spring constant, k = 0.3 N/m

Explanation:

It is given that,

Force acting on DNA molecule, $F=1.5\ nN=1.5\times 10^{-9}\ N$

The molecule got stretched by 5 nm, $x=5\times 10^{-9}\ m$

Let k is the spring constant of that DNA molecule. It can be calculated using the Hooke's law. It says that the force acting on the spring is directly proportional to the distance as :

$F=-kx$

$k=\dfrac{F}{x}$

$k=\dfrac{1.5\times 10^{-9}\ N}{5\times 10^{-9}\ m}$

k = 0.3 N/m

So, the spring constant of the DNA molecule is 0.3 N/m. Hence, this is the required solution.

8 0

4 years ago