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faust18 [17]
3 years ago
5

A 2 kg book is sitting on a table. A 10 N force is pulling it to the right. A 3 N force is pulling to the left. What is the Net

Force acting on the book? A. 2 N down B. 7 N to the right C. 13 N to the right D. 15 N to the right
Physics
1 answer:
ella [17]3 years ago
6 0

Here's the 'vector equation' for that situation:

                  (10N right)  +  (3N left)

               = (10N right)  +  (-3N right)

               =     7N right . 
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Two trains move towards each other on a straight track/railroad. The left train has a constant speed of 29ms, the right train ha
laiz [17]

Answer:

The left train travels 2378 m until it reaches the meeting point.

Explanation:

The equation for the position of the trains is the following:

x = x0 + v · t

Where:

x = position at time t

x0 = initial position

v = velocity

t = time

If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.

At the meeting point, the position of both trains is the same:

x left train = x right train

x0₁ + v₁  ·t = x0₂ + v₂ · t

0m + 29 m/s · t = 4744.6 m - 29 m/s · t

58 m/s · t = 4744.6 m

t = 4744.6 m / 58 /s

t = 82 s

The position of the left train at that time will be:

x = x0 + v · t

x = 0 m + 29 m/s · 82 s

x = 2378 m

The left train travels 2378 m until it reaches the meeting point.

7 0
3 years ago
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Y_Kistochka [10]

Answer:

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Explanation:

3 0
2 years ago
The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?
Daniel [21]

Answer:

7.77 x 10⁸ Km

Explanation:

given,

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now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

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The Jupiter is 7.77 x 10⁸ Km far from sun.

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