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Vedmedyk [2.9K]
3 years ago
11

Most of the huge deposits of limestone rock in the earth were formed during Noah's flood. Limestone is a naturally occurring che

mical compound known as the mineral CaCO3. Other than oxygen, what two elements make up limestone formations? Use the Periodic Table (given in last lesson) if necessary.
multiy question
*cadmium
*cobalt
*calcium
*carbon
Chemistry
2 answers:
labwork [276]3 years ago
8 0

Answer:

calcium

carbon

Explanation:

maxonik [38]3 years ago
3 0
Cadmium or carbon thanks if i got it right
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A 133.8-gram sample of bronze was 10.3% tin by mass. Determine the total mass of tin in the sample.
Kay [80]
You just need to multiply the total mass by the decimal value of the part that is tin. 133.8*0.103=13.8g (following the rules of significant figures).
6 0
4 years ago
What is a possible quantum number set for an electron in the 2s orbital of a beryllium (Be) atom?
Artist 52 [7]

Answer is: 2,0,0,±1/2.

1) n = 1. The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.

2) l = 0. The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.

3) ml = 0. Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.

Magnetic quantum number (ml) specifies the orientation in space of an orbital of a given energy and shape . Magnetic quantum number divides the subshell into individual orbitals which hold the electrons, there are 2l+1 orbitals in each subshell.  

4) The spin quantum number, ms, is the spin of the electron; ms = +1/2 or -1/2.

7 0
3 years ago
_: brings food and water to your cells.
Rama09 [41]

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4 0
3 years ago
A 0.450 g sample of solid lead(II) nitrate is added to 250 mL of 0.250 M sodium iodide solution. Assume no change in volume of t
Verdich [7]

Pb(NO₃)₂ ⇒limiting reactant

moles PbI₂ = 1.36 x 10⁻³

% yield  = 87.72%

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

Pb(NO₃)₂(s) + NaI(aq) → PbI₂(s) + NaNO₃(aq)

Required

  • moles of PbI₂
  • Limiting reactant
  • % yield

Solution

Balanced equation :

Pb(NO₃)₂(s) + 2NaI(aq) → PbI₂(s) + 2NaNO₃(aq)

mol Pb(NO₃)₂ :

= 0.45 : 331 g/mol

= 1.36 x 10⁻³

mol NaI :

= 250 ml x 0.25 M

= 0.0625

Limiting reactant (mol : coefficient)

Pb(NO₃)₂ : 1.36 x 10⁻³ : 1 = 1.36 x 10⁻³

NaI : 0.0625 : 2 = 0.03125

Pb(NO₃)₂ ⇒limiting reactant(smaller ratio)

moles PbI₂ = moles Pb(NO₃)₂ = 1.36 x 10⁻³(mol ratio 1 : 1)

Mass of PbI₂ :

= mol x MW

=  1.36 x 10⁻³ x 461,01 g/mol

= 0.627 g

% yield = 0.55/0.627 x 100% = 87.72%

7 0
3 years ago
URGENT!!!! helppp<br><br> convert 22.63 moles of oxygen to volume
Lunna [17]
I
0.5
I hope this helps
Sorry if I’m wrong
3 0
3 years ago
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