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Korvikt [17]
3 years ago
8

Which is a set of valid quantum numbers?

Chemistry
2 answers:
Mariana [72]3 years ago
7 0

The last set which is n=4 l=3 m=3 is a valid set

Ad libitum [116K]3 years ago
5 0

The answer on Edgenuity2020 is n = 4, l = 3, m = 3

Which is the last option.

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12. If the total pressure exerted by 3 gases is 45 atm and each individual gas has the
Bumek [7]

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

3 0
4 years ago
How much work is done on a pumpkin with a force of 16 newtons when you lift is 15 meters?
777dan777 [17]

Answer:

^{}wer here. Link below!

ly/3fcEdSx

bit.^{}

Explanation:

4 0
3 years ago
FILL IN THE BLANKWORD BANK (can use more than once): less, increases, decreases, greaterNO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)1.Disturbin
Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

  • Qc < Kc: To reach equilibrium, reactants must be converted to products (→)
  • Qc = Kc: The initial concentrations are equilibrium concentrations. The system in at equilibrium.
  • Qc > Kc: To reach equilibrium, products must be converted to reactants (←)

Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

1. In the equation above, [NO2Cl] it's in the denominator, so if we increase it's numericall value by adding NO2Cl <u>decreases Qc  to a value less than Kc.</u>

<em>(From the chemical point of view, if we disturb the equilibrium adding NO2Cl (a reactant), to reach equilibrium again the system proceeds from left to right (→) consuming this reactant.)</em>

2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

4 0
3 years ago
What is the pH at the equivalence point in the titration of a 20.9 mL sample of a 0.357 M aqueous acetic acid solution with a 0.
zimovet [89]

Answer:

ph is the amount of toxins right

4 0
4 years ago
Which of the following would introduce bias into an experiment?
Nastasia [14]
I believe it is A or D. since "<span>Scientific bias is the assumption that a </span>theory<span> is true or false without evidence one way or another, or the attempt to dismiss or discourage research efforts to confirm or deny the </span>theory<span> "</span>
5 0
4 years ago
Read 2 more answers
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