Melting (solid to liquid)
<u>Answer:</u> The mass of water that should be added in 203.07 grams
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
![\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolality%7D%3D%5Cfrac%7Bm_%7Bsolute%7D%5Ctimes%201000%7D%7BM_%7Bsolute%7D%5Ctimes%20W_%7Bsolvent%7D%5Ctext%7B%20%28in%20grams%29%7D%7D)
Where,
m = molality of barium iodide solution = 0.175 m
= Given mass of solute (barium iodide) = 13.9 g
= Molar mass of solute (barium iodide) = 391.14 g/mol
= Mass of solvent (water) = ? g
Putting values in above equation, we get:
![0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g](https://tex.z-dn.net/?f=0.175%3D%5Cfrac%7B13.9%5Ctimes%201000%7D%7B391.14%5Ctimes%20W_%7Bsolvent%7D%7D%5C%5C%5C%5CW_%7Bsolvent%7D%3D%5Cfrac%7B13.9%5Ctimes%201000%7D%7B391.14%5Ctimes%200.175%7D%3D203.07g)
Hence, the mass of water that should be added in 203.07 grams
Thunderstorms between Tampa and titusville
Answer: This is only a guess: The "following chemical formula: " doesn't appear on my screen. But since you mentioned Mg and Cl, I would guess MgCl2
Explanation: Mr loses 2 electrons while each Cl gains one each: Two chlorines for every 1 magnesium.