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2 years ago

Kinds of solar power stations

1 answer:

7 0

There are Three main types of concentrating solar thermal power systems: linear concentrating systems, which include public Troughs and linear fresnel reflectors. solar power towers.

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A 2000 kg car accelerates from 0 to 25 m / s in 21.0 s. How much is the average power delivered by the motor? (1 hp = 746 W)

mash [69]

Answer: 40.2 hp

Explanation:

The mass of the car is 2000kg.

in 21 seconds, it accelerates from 0m/s to 25m/s, so the average acceleration is:

a = (25m/s)/(21s) = 1.2 m/s^2

We know that force = mass*acceleration, then:

F = 2000kg*1.2m/s^2 = 2400N.

Now, the Power can be written as:

P = W/t where W is work = F*d (force per distance) and t is time.

then we have:

P = (F*d)/t and d/t is the average velocity, and we know the velocity v = 25m/s, so the average velocity will be (1/2)*25m/s = 12.5m/s

P = F*12.5m/s

and the force is F = 2400N

P = 2400 N*12.5m/s = 30,000 W

and we know that 1hp = 746 W

then, P = (30,000/746) hp = 40.2 hp

3 0

2 years ago

Read 2 more answers

LETS TALK ABOUT ANYTHING!!! <br> IS IT NORMAL TO ALWAYS BE SAD??? like all the time........

Gennadij [26K]

Umm, not normal or healthy but common
could be depression

5 0

2 years ago

Read 2 more answers

You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gasoline and

andreev551 [17]

Answer:

v_avg = 37 km/h

Explanation:

To find the average velocity in the complete trajectory you use the following formula:

$v_{avg}=\frac{v_1+v_2}{2}$ ( 1 )

v1: velocity in the first part of the trajectory = 70 km/h

v2: velocity in the second part of the trajectory = ?

You calculate v2 by using the following equation for a motion with constant velocity:

$v_2=\frac{2.0km}{30min}*\frac{60min}{1h}=4\frac{km}{h}$

you replace the values of v1 and v2 in (1) and you obtain:

$v_{avg}=\frac{70km/h+4km/h}{2}=37\frac{km}{h}$

hence, the average velocity is 37 km/h

6 0

2 years ago

Read 2 more answers

You have a string with a mass of 0.0127 kg. You stretch the string with a force of 9.33 N, giving it a length of 1.93 m. Then, y

melomori [17]

Answer:

wavelength = 0.968 m

frequency = 39.02 Hz

Explanation:

given data

mass = 0.0127 kg

force = 9.33 N

length = 1.93 m

to find out

wavelength and Frequency

solution

we know here linear density that is

linear density = $\frac{mass}{length}$ .........1

linear density = $\frac{0.0127}{1.93}$

linear density = 6.5803 × $10^{-3}$ kg/m

wavelength will be here

wavelength = $\frac{2L}{n}$ ..............2

here n = 4 for forth harmonic

wavelength = $\frac{2*1.93}{4}$

wavelength = 0.968 m

and

frequency will be for 4th normal mode of vibration is

frequency = $\frac{4}{2L} \sqrt{\frac{tension}{linear\ density} }$ ..........3

frequency = $\frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }$

frequency = 1.036269 × 37.654594

frequency = 39.02 Hz

5 0

2 years ago

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state

Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, $u_x=ucos\theta=8.6\ m/s$

Initial vertical velocity, $u_y=usin\theta=10.5\ m/s$

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

$H=\dfrac{(u\ sin\theta)^2}{2g}$

g is the acceleration due to gravity

$H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m$

The total maximum height, h' = h + H

$h'=44+5.625=49.625\ m$

The formula for the time of flight is given by :

$t_{max}=\dfrac{u\ sin\theta}{g}$

$t_{max}=\dfrac{10.5}{9.8}=1.07\ s$

Hence, this is the required solution.

3 0

3 years ago