CaCO₃ → CaCl₂
Ca = 40, C = 12, O = 16, Cl = 35.5
100 →111
3 → x
x = 3.33g
Answer:
one sigma
As for the bonding, there is one sigma and one pi bond formed between sulphur and the two oxygen atoms. The atom will also accommodate one lone pair
1. Take 100ml of water as solvent and boil it few minutes.
2. Now add one tea spoon sugar, one tea spoon tea leaves and 50ml of milk. Here sugar, tea leaves and milk are solute.
3. Now boil it again for few minutes so that sugar will dissolves in solution as sugar is soluble in water
4. Now filter the solution. Collect the filtrate in cup. The insoluble tea leaves will be left behind as residue.
Answer:
Explanation:
<u>1) Data:</u>
- T₁ = 25°C = 25 + 273.15 K = 298.15 K
- T₂ = 20°C = 20 + 273.15 K = 293.15 K
<u>2) Formula:</u>
Used combined law of gases:
<u>3) Solution</u>:
Solve the equation for V₂:
Substitute and compuite:
- V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)
You can learn more about gas law problems reading this other answer on Brainly: brainly.com/question/12732788.
