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3 years ago

Which of the following expressions represents the distance between 3/4 and 2

Mathematics

1 answer:

Anettt [7]3 years ago

6 0

Answer:

Im not sure what the following expressions are but the answer to the distance between 3/4 and 2 is 5/4 or just 1 1/4...

Not sure if this was what you were trying to ask but hope this helps

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cehgg A costing system that first assigns costs to activities and then to products is a.job-order costing. b.activity-based cost

Ronch [10]

Answer:b.activity-based costing.

Step-by-step explanation: Activity-based costing is a costing system that first talkies or identifies the activities that are involved in the Manufacturing or in a particular process and them assigns cost to such activities. This type of costing gives high premium or focus on the activities as it assigns cost to products based on the activities that led to the production of the products.

THIS TYPE OF COSTING IS ALSO KNOWN AS ABC APPROACH TO COSTING IT FIRST ASSIGN RESOURCES TO ACTIVITIES AND FROM ACTIVITIES TO PRODUCTS BASED ON THE CONSUMPTION ESTIMATES.

8 0

3 years ago

The sum of all but one interior angle of a heptagon is 776°. The final angle must have a measure of

shutvik [7]

A heptagon has 7 sides.

Sum of all interior angles = (7 - 2) x 180 = 900°

900 - 776 = 124°

Answer: The final angle must be 124°

5 0

3 years ago

Read 2 more answers

Rico made a function table to illustrate the rate he charges for mowing lawns. Complete the table. Then write a function rule fo

Lesechka [4]

I think the correct answer is C. i hope this helps

7 0

3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago

The 2 main support rods for a barbeque grill are each 7.5 cm from the centre of the

sukhopar [10]

Answer:

58.1 cm

Step-by-step explanation:

The length of each support rod can be found using the Pythagorean theorem. The geometry can be modeled by a right triangle, such that the distance from centre is one leg and half the length of the rod is the other leg of a triangle with hypotenuse equal to the radius of the grill.

<h3>Pythagorean theorem</h3>

The theorem tells us that the sum of the squares of the legs of a right triangle is the square of the hypotenuse. For legs a, b and hypotenuse c, this is ...

c² = a² +b²

<h3>application</h3>

For the geometry of the grill, we can define a=7.5 and c=30. Then b will be half the length of the support rod.

30² = 7.5 +b²

b² = 900 -56.25 = 843.75

b = √843.75 ≈ 29.0473

The length of each support rod is twice this value, so ...

rod length = 2b = 2(29.0473) = 58.0947

Each support rod is about 58.1 cm long.

7 0

2 years ago