1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
3 years ago
14

Use this free body diagram to help you find the magnitude of the force F2 needed to keep this block in static equilibrium. WILL

GIVE BRAINLIEST

Physics
1 answer:
oksian1 [2.3K]3 years ago
4 0
Static equilibrium means that all forces are equal, so make this easiest you want to break F1 into it's horizontal and vertical components. As there are no other forces acting in the horizontal, we know the horizontal component of F1 is 40N. This allows the vertical component to be found using pythagorus theorem. After finding the vertical and horizontal components, you just have to add the vertical components to find the difference between the up and down.

You might be interested in
Michael Scott is driving through the parking lot and accidentally hits Meredith as she’s walking to her car. If his car makes co
fiasKO [112]
Yes she's dead or in the hospital
6 0
3 years ago
HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in
In-s [12.5K]
Talk about the jobs that pipeline construction provides to citizens and wether or not it’s effects are ultimately eco-friendly
6 0
3 years ago
A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A
ANEK [815]

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J

So, the gravitational potential energy of a squirrel is 53.312 J.

7 0
3 years ago
Please someone help, I’m very confused and it’s due soon, thanks
Anit [1.1K]

Answer:

  1. 1 s
  2. 19.6 m
  3. 2 s
  4. 0.8 m/s^2
  5. 28 m/s
  6. 79 m/s
  7. 0.37 s
  8. 26 m/s
  9. 242 m/s
  10. 19,930 m

Explanation:

In physics, many of the relationships between speed, distance, and acceleration are tied up in the equations for potential and kinetic energy. For an object of mass M* at height h in a gravity field with acceleration g, the potential energy is

  PE = Mgh

At velocity v, the kinetic energy of the object is ...

  KE = 1/2Mv^2

When an object is dropped or launched from rest, the height and velocity are related by the fact that kinetic energy gets translated to potential energy, or vice versa. This gives rise to ...

  PE = KE

  Mgh = (1/2)Mv^2

The mass (M) can be factored out of this, so we have ...

  2gh = v^2

This can be solved for height:

  h = v^2/(2g) . . . . [eq1]

or for velocity:

  v = √(2gh) . . . . [eq2]

__

When acceleration is constant, as assumed here, the velocity changes linearly (to/from 0). So, over the time of travel, the average velocity is half the final velocity. That is,

  t = 2h/v

Depending on whether you start with h or with v, this resolves to two more equations:

  t = 2(v^2/(2g))/v = v/g . . . . [eq3]

  t = 2h/(√(2gh)) = √(4h^2/(2gh)) = √(2h/g) . . . . [eq4]

The last of these can be rearranged to give distance as a function of time:

  h = gt^2/2 . . . . [eq5]

or acceleration as a function of time and distance:

  g = 2h/t^2 . . . . [eq6]

__

These 6 equations can be used to solve the problems posed. Just "plug and chug." For problems in Earth's gravity, we use g=9.8 m/s^2. (You may want to keep these equations handy. Be aware of the assumptions they make.)

_____

* M is used for mass in these equations so as not to get confused with m, which is used for meters.

_____

1) Use [eq4]: t = √(2·6 m/(9.8 m/s^2)) ≈ 1.107 s ≈ 1 s

__

2) Use [eq5]: h = (9.8 m/s^2)(2 s)^2/2 = 19.6 m

__

3) Use [eq4]: t = √(25 m/(4.9 m/s^2)) ≈ 2.259 s ≈ 2 s

__

4) Use [eq6]: g = 2(10 m)/(5 s)^2 = 0.8 m/s^2

__

5) Use [eq2]: v = √(2·9.8 m/s^2·40 m) = 28 m/s

__

6) Use [eq2]: v = √(2·9.8 m/s^2·321 m) ≈ 79.32 m/s ≈ 79 m/s

__

7) Using equation [eq3], we will find the time until Tina reaches her maximum height. Her actual off-the-ground total time is double this value. Using [eq3]: t = v/g = (1.8 m/s)/(9.8 m/s^2) = 9/49 s. Tina is in the air for double this time:

  2(9/49 s) ≈ 0.37 s

__

8) Use [eq2]: v = √(2·9.8 m/s^2·33.5 m) ≈ 25.624 m/s ≈ 26 m/s

__

9) Use [eq2]: v = √(2·9.8·3000) m/s ≈ 242.49 m/s ≈ 242 m/s

(Note: the terminal velocity in air is a lot lower than this for an object like a house.)

__

10) Use [eq1]: h = (625 m/s)^2/(2·9.8 m/s^2) ≈ 19,930 m

_____

<em>Additional comment</em>

Since all these questions make use of the same equation development, I have elected to answer them. Your questions are more likely to be answered if you restrict your posts to 3 or fewer questions each.

5 0
3 years ago
A Rac variant, in which the residue at position 61 was replaced with an alanine (Rac61A), was synthesized. Wild-type Rac and Rac
ludmilkaskok [199]

Answer:

Ammonia, (NH_{3})

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3}) and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>

3 0
3 years ago
Other questions:
  • It takes 56.5 kilojoules of energy to raise the temperature of 150 milliliters of water from 5°C to 95°C. If you
    6·1 answer
  • Two of the three tuning forks have known frequencies. When a 510 Hz. fork and the unknown fork are struck together, four beats p
    7·1 answer
  • In an out of control ceramics workshop, two clay balls collide in mid air and stick together. the first has mass 3.1 kg and coll
    7·1 answer
  • A child is riding a bike at a speed of 6m/s with a total kinetic energy of 1224J. If the mass of the child is 30kg, what is the
    8·1 answer
  • A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
    8·1 answer
  • A bullet with a mass of 0.040 kg collides inelastically with a wooden block of mass 1.5 kg, initially at rest. After the collisi
    14·1 answer
  • a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box
    9·1 answer
  • EASY BRAINLIEST PLEASE HELP!!
    5·2 answers
  • A uniform metal bar of length 6m and mass 100kg rest with its upper end against a smooth vertical wall and with its lower end on
    13·1 answer
  • A 30 ohm resistor and a 20 ohm resistor are
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!