An error in witch macromolecule is the cause of hemophilia
2 answers:
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The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency ( ) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
=
where :
comparing the general form with the given equation
= 18.2329
hence the short period oscillation frequency ( ) = 0.063 rad/sec
phugoid oscillations natural frequency ( ) = 4.27 rad/sec
