Answer:
-x¹⁴ / 5040
-½ < x < ½
Step-by-step explanation:
f(x) = e^(-x²)
The Taylor series for eˣ centered at 0 is:
eˣ = ∑ (1/n!) xⁿ
Substitute -x²:
e^(-x²) = ∑ (1/n!) (-x²)ⁿ
e^(-x²) = ∑ (1/n!) (-1)ⁿ x²ⁿ
The 14th degree term occurs at n=7.
(1/7!) (-1)⁷ x¹⁴
-x¹⁴ / 5040
ln(1 + x) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ xⁿ / n
If we substitute 4x²:
ln(1 + 4x²) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ (4x²)ⁿ / n
Using ratio test:
lim(n→∞)│aₙ₊₁ / aₙ│< 1
lim(n→∞)│[(-1)ⁿ⁺² (4x²)ⁿ⁺¹ / (n+1)] / [(-1)ⁿ⁺¹ (4x²)ⁿ / n]│< 1
lim(n→∞)│-1 (4x²) n / (n+1)│< 1
4x² < 1
x² < ¼
-½ < x < ½
Answer:
Ok, here goes: f(3) means take f(x) and plug in 3 wherever we see x. So
f(3) = 12*39 + 3 = 236196 + 3
f(3) = 236199
Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x. So
f(-3) = 12*(-3)9 + (-3) = -236196 - 3
f(-3) = -236199
Putting those two things together, we get
f(3) + f(-3) = 236199 - 236199 = 0
Step-by-step explanation:
First break the L into two rectangular prisms and then find the volume for each prism. Then add those two volumes together to get the L.
Start by distributing the exponent to each of the terms in 
. This will become 
, and 
. Now, the expression is:
.
We can now simplify the bottom to read: 
because when multiplying variables raised to an exponent, we add the exponents. The expression now looks like:
The 2/8 simplifies to 1/4:
Now, we have two u terms on the top and bottom. When dividing variables raised to an exponent, we subtract the exponents. However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent. The final answer is:
Hope this makes sense!!
