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3 years ago

Can someone please explain this to me? I need help

Chemistry

2 answers:

Vladimir [108]3 years ago

6 0

Answer:

The order would be: X-Rays, Visible Light, and Infrared Waves.

X-Rays have the shortest wavelength out of all three, then Visible Light, and Infrared Waves have the longest wavelength of the three.

Explanation:

So basically, the LONGER the wavelength, the lower the energy. and the SHORTER the wavelength, the higher the energy. For example, Radio waves are the WEAKEST out of all the types of waves because they have the LONGEST wavelengths. Gamma Rays are the STRONGEST out of all the types of waves because they have the SHORTEST wavelengths. So Radio Waves have the lowest energy, and Gamma Rays have the highest energy.

Here is a list of all the types of waves in order from shortest wavelength to longest wavelengths:

Gamma Rays (Shortest Wavelengths, High Energy), then X-Rays would be the second strongest, then Ultraviolet waves, then Visible Light, then Infrared waves, then Microwaves, and lastly Radio Waves (Longest Wavelengths, Low Energy).

skelet666 [1.2K]3 years ago

6 0

Answer:

X rays < red visible < infrared

Explanation:

According to your picture, gamma rays have the shortest wavelength and radio waves have the longest.

Thus. the order of wavelengths is

X rays < red visible < infrared

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The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

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The allowable combination for the atomic orbital is n=3, l=1, $m_{l}$ =-1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Since $m_{l}$ values are integers from -l to 0 to +l, for l = 0 the value of $m_{l}$ cannot be -1 (l = 0 has $m_{l}$ = 0).

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Therefore, the allowable condition is n=3, l=1, $m_{l}$ =-1.

To know more about quantum numbers, visit: brainly.com/question/16979660

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Can someone please explain this to me? I need help ​

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