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dimulka [17.4K]
3 years ago
12

What is the land area from which a stream gets its water ?

Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0
Drainage basin. the land area from which a stream gets its water, also called a watershed.
Hope this helped ^^
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What's the amount of solute in 1.75 L of 0.25 M HCl?
Fynjy0 [20]

Answer: 0.4375 mols of solute

Explanation:

The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is M=\frac{mols of solute}{liters of solution}. Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.

0.25M=\frac{x}{1.75L}                        [multiply both sides by 1.75 L]

x=0.4375 mols

There are 0.4375 mols of solute.

5 0
4 years ago
The strongest substance in your body is:
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The enamel is the strongest substance in our bodies mainly inside your mouth.
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A substance placed in a container has a fixed volume and takes up the shape of the container. In which state does this substance
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Liquid 
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8 0
4 years ago
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Provided is a diagram showing forces on a box.
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4 0
3 years ago
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con
anyanavicka [17]

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 }  *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O}  *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

5 0
3 years ago
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