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3 years ago

As a longitudinal wave moves through a medium,

Physics

1 answer:

saul85 [17]3 years ago

4 0

1) Vibrate Parallel to the direction of the wave's propagation

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What factors affect the speed of water waves

Aneli [31]

Hey there,

Your question states: What factors affect the speed of water waves
Let's get one thing out the way, (wavelength) does $NOT$ affect the the speed of water. If anything, it would be how high the wavelength's are. The higher the wavelengths are, the more that it would affect the speed, because there very high, but if it were to go longer on the width side, that would increase the speed, but that's not the case. Your correct answer would be (higher wavelength).

Hope this really helps you.

6 0

3 years ago

You are doing an experiment to determine your reaction time. Your friend holds a ruler. You place your fingers near the sides of

olga2289 [7]

I'm guessing that you mean like this:
-- The ruler is held with zero at the bottom, and the centimeter markings
    increase as you go up the ruler.
-- You place your fingers with the ruler and the zero mark between them.
-- The number where you catch the ruler is the distance it has fallen.

Then, all we have to find is the time it takes for the ruler to fall 11.3 cm .

Here's the formula for the distance an object falls from rest
in a certain time:

Distance = (1/2) (gravity) (time)²

On Earth, the acceleration of gravity is 9.8 m/s².
So we can write ...

      11.2 cm = (1/2) (9.8 m/s²) (time)²
or
       0.112 meter = (4.9 m/s²) (time)²

Divide each side
by 4.9 m/s² : (0.112 m) / (4.9 m/s²) = time²

(0.112 / 4.9) sec² = time²

Square root
each side:    time = √(0.112/4.9 sec²)

= √ 0.5488 sec²

=    0.74 second (rounded)

4 0

3 years ago

Read 2 more answers

You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart

hichkok12 [17]

Answer:

$v = 3.5 \times 10^5 m/s$

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

$\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}$

now we have

$\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}$

$\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}$

so we will have

$r = 3.46 \times 10^8 m$

Now by energy conservation

$-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}$

$-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5$

$v = 3.5 \times 10^5 m/s$

7 0

3 years ago

30 points, brainiest, high school physics problem, please help with explanations.

Ymorist [56]

Answer:

I think the answer is C too

4 0

3 years ago

A student made the claim that a 4 gram paintball fired from a paintball gun at 90 m/s could have about the same kinetic energy a

Fiesta28 [93]

Answer:

I do agree with the student. Because imagene you have a tissue and a stick. And you throw them at the same speed , the stick will go farther because it' s heavier but the tissue would just blow around and not go forward because it is not heavy enought.

Explanation:

Hope this is correct have a terrific day.

5 0

3 years ago