As a longitudinal wave moves through a medium,

In terms of the dc current I, how much magnetic energy is stored in the insulating medium of a 3- m-long, air –filled section of

Alexxandr [17]

Answer:

The answer is 138.5

Explanation:

STEP 1:

The inductance per unit length of a coaxial transmission line is

L′=L/ I

=Ø/H

=μoI/2π In (b/a)

In this a is the radius of inner conductor

b is the radius of outer conductor

I is the coaxial transmission

μ is the magnetic permeability

Since the transmission of the charge exists in air, the value of the relative permeability is μr= I and permeability of free space is μo= 4π x 10-7 H/m . So the magnetic permeability will be

μ = μoμ r

μ =μ o(I) 4π x 10-7 H/m

L′= μoI/2π In (b/a)

= (4π x 10-7 ) (2)/2π In (10/5)

=2.77 x 10-7 H

STEP 2:

Obtain the magnetic energy stores in the magnetic field H of a volume of the coaxial transmission line containing a material with permeability μ, by using the formula given below:

Wm= 1/2 LI^2

= 1/2 (2.77x 10^-7 I^2

= 138.5 X 10^-9 I^2 J

Now we will simplify the equation

Wm= 185.5I^2 nJ

So, the magnetic energy stored in insulating medium is 185.5I^2 nJ

6 0

3 years ago

A solenoidal coil with 25 turns of wire is wound tightly around another coil with 300 turns. The inner solenoid is 25.0 cm long

joja [24]

Answer:

$5.65487\times 10^{-8}\ Wb$

$1.17\times 10^{-5}\ H$

-0.020475 V

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

$N_1$ = Number of turns of coil = 25

$N_2$ = Number of turns of coil 2 = 300

$\frac{di_2}{dt}$ = Rate of current increased = $1.75\times 10^3\ A/s$

d = Diameter = 2 cm

r = Radius = $\frac{d}{2}=\frac{2}{2}=1\ cm$

A = Area = $\pi r^2$

Magnetic field in the solenoid is given by

$B=\mu_0\frac{N_2}{l}I\\\Rightarrow B=4\pi\times 10^{-7}\frac{300}{0.25}\times 0.12\\\Rightarrow B=0.00018\ T$

Magnetic flux is given by

$\phi=BA\\\Rightarrow \phi=0.00018\times \pi\times 0.01^2\\\Rightarrow \phi=5.65487\times 10^{-8}\ Wb$

The average magnetic flux through each turn of the inner solenoid is $5.65487\times 10^{-8}\ Wb$

Mutual inductance is given by

$L=\frac{N_1\phi}{i_1}\\\Rightarrow L=\frac{25\times 5.65487\times 10^{-8}}{0.12}\\\Rightarrow L=1.17\times 10^{-5}\ H$

The mutual inductance of the two solenoids is $1.17\times 10^{-5}\ H$

Induced emf is given by

$V=-L\frac{di_2}{dt}\\\Rightarrow V=-1.17\times 10^{-5}\times 1.75\times 10^3\\\Rightarrow V=-0.020475\ V$

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.020475 V

5 0

3 years ago

Which of the following statements is true concerning mechanical waves and electromagnetic waves?

Over [174]

Answer:

B

Explanation:

Electromagnetic spectrum includes visible light which we see all the time reflecting off objects to give them colours, mechanical waves like sound require something to move in, its the reason why people say you can't scream in space because space is a giant vacuum. No not the kind you use to clean up the mess you made from breakfast. The kind that has no air. So sound can be heard on earth as it is not a vacuum, air moves freely and transfers sounds vibrations all around you to be absorbed by walls and other stuff in comes in contact with.

Extra information:

Sound travels further in water because the molecules are closer together meaning that transferring the energy is easier. This is how Blue wales can communicate from hundreds of miles away.

3 0

3 years ago

An object of mass m is initially at rest and free to move without friction in any direction in the xy-plane. A constant net forc

Dominik [7]

Answer:3/5

Explanation:

6/6

3 0

3 years ago

The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object

Gennadij [26K]

Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation: 1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.

3 0

4 years ago

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