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3 years ago

Define newton's 3rd law of motion

Physics

1 answer:

soldier1979 [14.2K]3 years ago

7 0

Answer:

For every action, there is an equal and opposite reaction.

Explanation:

Let's say I threw a ball on the wall. The image shows the instance the ball comes into contact with the wall.

If you would look at the image above,

- F1 and F2 are acting in opposite directions.

- They both have the same magnitude too.

F1 is the force of the ball on the wall (action force) and F2 is the force of the wall on the ball (reaction force). This is called an action-reaction pair.

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The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.

sergiy2304 [10]

The average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

$Intensity = Rate of energy radiated/4\pi R^{2}$

where R is the distance of the earth from the sun.

$I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}$

$I=0.12597*10^{12}$

$I=12.6*10^{10} W/m^{2}$

What is the meaning of the intensity of sunlight?

Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.

What is the average intensity received on the Earth's surface?

The average intensity received on the Earth's surface is given by:

$I=rate of energy radiated/4\pi R^{2}$

Thus, the average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

To know more about the intensity received from the sun:

brainly.com/question/29579262

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8 0

1 year ago

Can an objects displacement be greater than or equal to the objects distance?

Reptile [31]

If you say displacement is greater than distance, you will contradict the above statement. Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector.So' displacement cannot be more than distance.

6 0

4 years ago

How are earthquakes distributed on the map

Ira Lisetskai [31]

On the map red bands represent the earthquake

6 0

3 years ago

A basketball player standing up with the hoop launches the ball straight up with an initial velocity of v_o = 3.75 m/s from 2.5

denis23 [38]

Answer:

a) The maximum height the ball will achieve above the launch point is 0.2 m.

b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.

Explanation:

For the height reached, we use 3rd equation of motion:

2gh = Vf² - Vo²

Here,

Vo = 3.75 m/s

Vf = 0m/s, since ball stops at the highest point

g = -9.8 m/s² (negative sign for upward motion)

h = maximum height reached by ball

therefore, eqn becomes:

2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²

h = 0.2 m

To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:

2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²

(Vo)² = 19.6 m²/s²

Vo = √19.6 m²/s²

Vo = 4.43 m/s

Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)

Vo = 0.174 in/ms

6 0

3 years ago

Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg

KengaRu [80]

Answer

given,

speed of car = 60 km/hr

= 60 x 0.278 m/s

= 16.68 m/s

radius of the tire = 25 cm = 0.25 m

time taken to stop = 6 s

average acceleration = ?

$\omega = \dfrac{v}{R}$

$\omega = \dfrac{16.68}{0.25}$

$\omega =66.72 rad/s$

average acceleration= $\dfrac{\Delta \omega}{\Delta t}$

= $\dfrac{66.72}{6}$

= 11.12 rad/s²

correct answer option D

b) length of sea saw = 10 m

mass of jack = 100 Kg

mass of Jill = 60 Kg

Let y be the distance from the Jack. To balance the seesaw moment on both side should balance each other about fulcrum

now,

100 x y = 5 x 60

y = 3 m

the correct answer is option B

4 0

3 years ago