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3 years ago

Which one is it? WIll mark brainlist

Physics

2 answers:

maksim [4K]3 years ago

7 0

Answer:

Explanation:

Graph C represents a linear function. As the height increases by 1 meter, the gravitational energy increases by 10 joules respectively.

DochEvi [55]3 years ago

5 0

Graph c is the correct awnser, hope this helped

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An egg of mass 0.060 kg is dropped from the top of a building. Just before it reaches the ground, it has a total kinetic energy

3241004551 [841]

The velocity is 14 m/s

The parameters given on the question are

mass= 0.060 kg

kinetic energy= 5.9 joules

K.E= 1/2mv²

5.9= 1/2 × 0.060 × v²

5.9= 0.5 × 0.060v²

5.9= 003v²

v²= 5.9/0.03

v²= 196.66

v= √196.66

v= 14 m/s

Hence the velocity of the egg before it strikes the ground is 14 m/s

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3 0

3 years ago

an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE

KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in the problem, the initial momentum is

$p=mv=5.00 kg m/s$

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

So, the new momentum will be:

$p'=m'v'=(2m)(2v)=4(mv) = 4p = 4(5.00)=20 kg m/s$

So, the final momentum is 4 times the initial momentum.

Learn more about momentum:

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#LearnwithBrainly

6 0

4 years ago

Two balls have the same mass. One ball moving along the positive x axis and the other ball moving along the positive y axis unde

Paladinen [302]

In a completely inelastic collision, the two objects stick together after the collision.

7 0

3 years ago

Read 2 more answers

Scenario: You place a mug of hot tea on the table in a cool room.

Shkiper50 [21]

A. Radiation, conduction

B.
*Radiation will occur between the mug of hot tea and the room
*conduction will occur between the mug of hot tea and the table

C. The table as well as the surrounding air will become warmer.
This is because heat is given off from the mug of hot tea.

6 0

3 years ago

In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

6 0

3 years ago