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frez [133]
3 years ago
11

An airplane is pushed 22 degrees eastward off its northward course by a jet stream traveling at a speed of 136.73 km/hr. The new

speed is 365 km/hr. Find the plane's original velocity.
Physics
1 answer:
uranmaximum [27]3 years ago
3 0

As the speed of airplane is change due to jet stream

So the net speed is given as

v_{net} = v_{plane} + v_{stream}

now we can rearrange it as

v_{plane} = v_{net} - v_{stream}

now by the formula of vector difference we have

v_{plane} = \sqrt{v_{net}^2 + v_{stream}^2 - 2v_{net}v_{stream}cos\theta}

now plug in all values

v_{plane} = \sqrt{365^2 + 136.73^2 - 2* 365* 136.73*cos22}[tex]v_{plane} = 243.7 km/hr

so above is the speed of the plane

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What electric force would a stationary 3.8 C charge experience if it were far away from any other charges
MAVERICK [17]

Answer:

The electric force will be  0 N

Explanation:

From the question we are told that

   The magnitude of the charge is  q_1 = 3.8 \ C

   

Generally from Coulombs law the electric force  between two charges is mathematically represented as

         F = \frac{ k  *  q_1 q_2 }{r^2}

Here r is the distance of separation between that two charges.

  Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is  r = \infty

So

       F = \frac{ k  *  3.8  * q_2 }{\infty^2}

=>    F =0 \ N

Hence the electric force will be  0 N

3 0
3 years ago
Explain how a hydroelectric power plant converts energy stored in water into electricity
mart [117]
Hot water, as in very hot water, goes to steam with an enormous change in volume and pressure. This is capable of driving turbine blades, which in turn rotate enormous copper (eg) wired coils in enormous magnetic fields. This in turn produces electricity via electromagnetic induction and Fleming's right hand (I think it is) DYNAMO rule. That goes down miles and mile of v heavy conducting wire/cable as electricity.
4 0
3 years ago
A motorcycle is traveling up one side of a hill and down the other side. The crest of the hill is a circular arc with a radius o
Setler79 [48]

Answer:

21.8 m/s

Explanation:

At the top of the hill (crest), there are two forces acting on the motorcycle:

- The reaction force of the road, N (upward)

- The force of gravity, mg (downward)

Since the motorcycle is moving by circular motion, the resultant of these forces will give the centripetal force, so:

mg-N = m\frac{v^2}{r}

where the direction of the weight (mg) is equal to that of the centripetal force, and where

m is the mass of the cycle

g = 9.8 m/s^2 is the acceleration of gravity

v is the speed

r = 48.6 is the radius of the hill

The cycle loses contact with the road when the reaction force becomes zero:

N = 0

Substituting into the equation, we therefore find the maximum speed that is allowed for the cycle before losing constact:

mg = m\frac{v^2}{r}\\v=\sqrt{gr}=\sqrt{(9.8)(48.6)}=21.8 m/s

6 0
3 years ago
HELP MEEEEE HURRRYYYY EASYY
alisha [4.7K]

Answer:

C

Explanation:

thats what i think it depends on the amount of force someone dropped the ball with.

7 0
3 years ago
Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!
krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

L = 10 Log\frac{I}{I_0}

20 = 10 Log{I}{10^{-12}}

I_1 = 10^{-10}W/m^2

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

L = 10 Log\frac{I}{I_0}

50 = 10Log\frac{I}{10^{-12}}

I_2 = 10^{-7}W/m^2

now we know that

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}

r_2 = 47 cm

so now the distance from friend must be 47 cm

8 0
3 years ago
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