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Advocard [28]
2 years ago
13

A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to

both the rod and its velocity. If the length of the rod is doubled, what happens to the electric field in the rod
Physics
1 answer:
Alborosie2 years ago
6 0

Explanation:

If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :

\epsilon=Blv

The electric field in the conductor is given by :

E=\dfrac{\epsilon}{l}\\\\E=\dfrac{Blv}{l}\\\\E=Bv

It is clear that the electric field is independent of the length of the rod. If the length of the rod is doubled, the electric field in the rod remains the same.

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A hockey puck of mass m1=165 g slides from left to right with an initial velocity of 15.5 m/s. It collides head on with a second
Fynjy0 [20]

Answer:

it may be -6 m/s

Explanation:

3 0
3 years ago
A velocity selector, in which charged particles of a specific speed pass through undeflected while those of greater or lesser sp
uranmaximum [27]

Answer:

a) 351351.35m/s

b) 1.044*10^{-8}kg/C

Explanation:

a) Electric force and magnetic force over the charge must have the same magnitude. From there we can compute the seep of the charge.

F_E=F_B\\\\qE=qvB\\\\v=\frac{E}{B}=\frac{1.95*10^{5}V/m}{0.555T}=351351.35\frac{m}{s}

b) the mass-charge ratio is given by:

\frac{m}{q}=\frac{rB}{v}=\frac{(6.61*10^{-3}m)(0.555T)}{351351.35m/s}=1.044*10^{-8}\frac{kg}{C}

hope this helps!!

5 0
3 years ago
What does newton's second law of motion state?
telo118 [61]
<span>The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.</span>
8 0
3 years ago
Read 2 more answers
A 400g mass object at rest is acted on by a 200 N net force for 12 seconds. What is it’s final velocity?
Kisachek [45]

Explanation:

do we can say that the first step is finding the acceleration of the object. We do so by saying F = ma

so a = F/m

a = 500 m/s^2

we now have the time, acceleration and initial velocity.

so we can find the final velocity by using one of newtons equations which is: vf = vi + at

so:

vf = 0 + 500 × 12

vf = 6000

note that our initial velocity was zero since the object was initially at rest.

if you still have any doubt dont hesitate to ask for further help.

3 0
1 year ago
David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is th
inessss [21]

Answer:

630 km.

Explanation:

To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.

Case 1:

Speed 1 (S₁) = 65 km / hour

Time 1 (t₁) = 6 hours

Distance 1 (d₁) =?

Speed = Distance /time

S₁ = d₁ / t₁

65 = d₁ / 6

Cross multiply

d₁ = 65 × 6

d₁ = 390 Km

Case 2:

Speed 2 (S₂) = 80 km / hour

Time 2 (t₂ ) = 3 hours

Distance 2 (d₂) =?

Speed = Distance /time

S₂ = d₂ / t₂

80 = d₂ / 3

Cross multiply

d₂ = 80 × 3

d₂ = 240 Km

Finally, we obtained the total distance travelled by David as follow

Distance 1 (d₁) = 390 Km

Distance 2 (d₂) = 240 Km

Total Distance travelled (dₜ) =?

Total distance = distance 1 + distance 2

dₜ = d₁ + d₂

dₜ = 390 + 240

dₜ = 630 km

Therefore, the total distance travelled by David is 630 km

8 0
3 years ago
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