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Advocard [28]
3 years ago
13

A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to

both the rod and its velocity. If the length of the rod is doubled, what happens to the electric field in the rod
Physics
1 answer:
Alborosie3 years ago
6 0

Explanation:

If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :

\epsilon=Blv

The electric field in the conductor is given by :

E=\dfrac{\epsilon}{l}\\\\E=\dfrac{Blv}{l}\\\\E=Bv

It is clear that the electric field is independent of the length of the rod. If the length of the rod is doubled, the electric field in the rod remains the same.

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A spherical submersible 1.84 m in radius, armed with multiple cameras, descends under water in a region of the Atlantic Ocean kn
Drupady [299]

Answer:

23932242.5 Pa

Explanation:

P_a = Atmospheric pressure = 1.013\times 10^5\ Pa

P_w = Pressure of seawater

\rho = Density of sea water = 1.025\times 10^3\ kg/m^3

h = Depth of shipwreck = 2.37\times 10^3\ m

g = Acceleration due to gravity = 9.81 m/s²

The absolute pressure is given by

P_{ab}=P_a+P_w\\\Rightarrow P_{ab}=1.013\times 10^5+1.025\times 10^3\times 9.81\times 2.37\times 10^3\\\Rightarrow P_{ab}=23932242.5\ Pa

The absolute pressure at the depth of the shipwreck is 23932242.5 Pa

5 0
3 years ago
What property of matter do we consider when deciding whether to buy a half-gallon of milk at the store versus a gallon of milk?
Mrac [35]
Liquified matter maybe.
7 0
3 years ago
The Earth’s radius is 6378.1 kilometers. If you were standing at the equator, you are essentially undergoing uniform circular mo
emmainna [20.7K]

Answer:

b. 84 minutes

Explanation:

a_c=g = Centripetal acceleration = 9.81 m/s²

r = Radius of Earth = 6378.1 km

v = Velocity

Centripetal acceleration is given by

a_c=\dfrac{v^2}{r}\\\Rightarrow v=\sqrt{a_cr}\\\Rightarrow v=\sqrt{9.81\times 6378100}\\\Rightarrow v=7910.06706\ m/s

Time period is given by

T=\dfrac{2\pi r}{v60}\\\Rightarrow T=\dfrac{2\pi 6378.1\times 10^3}{7910.06706\times 60}\\\Rightarrow T=84.43835\ minutes

The time period of Earth’s rotation would be 84.43835 minutes

7 0
3 years ago
Patrick Mahomes is throwing a football with an applied force of 230 N but is experiencing air resistance of 30 N. The ball has a
Ganezh [65]

Answer:

www.chiefs.com

Web results

Patrick Mahomes

7 0
3 years ago
if a 60 kg person was standing on a platform at the surface of saturn and they jumped, they would have to push with a force grea
lidiya [134]

Answer:

A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N

Explanation:

The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object

Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object

The weight of the object on the surface of a planet = m × g

Where;

m = The mass of the object

g = The strength of gravity on the planet's surface in N/kg

The given parameters are;

The mass of the person standing on a platform at the surface of Saturn, m = 60 kg

The strength of gravity on the surface of Saturn = 9 N/kg

Therefore, we have;

The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N

Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.

4 0
3 years ago
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