Question

How many moles of a gas will 700 m hold at -100 oC and 86 atm?

Answer 1

0.23 moles of a gas will 700 m hold at -100 oC and 86 atm.

Explanation:

given that:

volume = 700 ml OR 0.7 Litre (for converting into litre it is divided with 1000 as 1 litre = 1000ml)

temperature = -100 degrees OR 173.15 K

pressure = 86 atm

R = 0.082057 L atm mol-1K-1

n=?

It is known that when Volume is taken in litres, pressure in atm, and temperature in Kelvin then R= 0.082057 L atm mol-1K-1,

From the formula for ideal gas:

PV = nRT

putting the values in the formula:

n = $\frac{RT}{PV}$

  = $\frac{0.0820507 X 173.15}{0.7 X 86}$

  = 0.23 moles of the gas will be required.