How many moles of a gas will 700 m hold at -100 oC and 86 atm?
1 answer:
0.23 moles of a gas will 700 m hold at -100 oC and 86 atm.
Explanation:
given that:
volume = 700 ml OR 0.7 Litre (for converting into litre it is divided with 1000 as 1 litre = 1000ml)
temperature = -100 degrees OR 173.15 K
pressure = 86 atm
R = 0.082057 L atm mol-1K-1
n=?
It is known that when Volume is taken in litres, pressure in atm, and temperature in Kelvin then R= 0.082057 L atm mol-1K-1,
From the formula for ideal gas:
PV = nRT
putting the values in the formula:
n =
=
= 0.23 moles of the gas will be required.
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Answer:
A) 100 mL
Explanation:
At constant temperature and number of moles, Using Boyle's law
Given ,
V₁ = 200 mL
V₂ = ?
P₁ = 60 kPa
P₂ = 120 kPa
Using above equation as:
Answer : The final temperature of the copper is,
Solution :
Formula used :
where,
Q = heat gained = 299 cal
m = mass of copper = 52 g
c = specific heat of copper =
= final temperature = ?
= initial temperature =
Now put all the given values in the above formula, we get the final temperature of copper.
Therefore, the final temperature of the copper is,