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kolezko [41]
3 years ago
6

How many moles of a gas will 700 m hold at -100 oC and 86 atm?

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0

0.23 moles of a gas will 700 m hold at -100 oC and 86 atm.

Explanation:

given that:

volume = 700 ml OR 0.7 Litre (for converting into litre it is divided with 1000 as 1 litre = 1000ml)

temperature = -100 degrees OR 173.15 K

pressure = 86 atm

R = 0.082057 L atm mol-1K-1

n=?

It is known that when Volume is taken in litres, pressure in atm, and temperature in Kelvin then R= 0.082057 L atm mol-1K-1,

From the formula for ideal gas:

PV = nRT

putting the values in the formula:

n = \frac{RT}{PV}

  = \frac{0.0820507 X 173.15}{0.7 X 86}

  = 0.23 moles of the gas will be required.

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The carbon-14 content of a wooden harpoon handle found in an Inuit archaeological site was found to be 61.9% of the carbon-14 co
astraxan [27]

Answer:

3,964 years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

  • The half-life of the element is 5,730 years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(5,730 years) = 1.21 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 1.21 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 100%).

[A] is the remaining concentration of the sample ([A] = 61.9%).

∴ t = (1/k) ln([A₀]/[A]) = (1/1.21 x 10⁻⁴ year⁻¹) ln(100%/61.9%) = 3,964 years.

7 0
4 years ago
A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure
lord [1]

Answer is:  the absolute pressure of the air in the balloon is 1.015 atm (102.84 kPa).

n = 0.250 mol; amount of substance.

V = 6.23 L; volume of the balloon.

T = 35°C = 308.15 K; temperature.

R = 0.08206 L·atm/mol·K, universal gas constant.

Ideal gas law: p·V = n·R·T.

p = n·R·T / V.

p = 0.250 mol · 0.08206 L·atm/mol·K · 308.15 K / 6.23 L.

p = 1.015 atm; presure of the air.

6 0
3 years ago
Herbie left his house at 3:30 p.m. and arrived at Kit’s house at 5:00 p.m. The two boys live 7 miles apart. What was Herbie’s av
Kisachek [45]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose they take t minutes to meet each other.

Distance covered by first friend in t minutes, = 0.2 *t=0.2∗t

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Total distance is given as 7, so

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SO. the average speed is 10m: Answer

5 0
3 years ago
What would happen if hydrogen and nitrogen combine?
Tanzania [10]
<span>At room temperature and atmospheric pressure, nothing happens when the two gasses are mixed. However, at high temperature and pressure (450C, 200atm), in the presence of an iron oxide catalyst, the production of ammonia is thermodynamically advantageous.</span>
5 0
3 years ago
How do you calculate the number of moles in CO2
gogolik [260]

Answer:

The number of molecules in a mole (known as Avogadro's constant) is defined such that the mass of one mole of a substance, expressed in grams, is equal to the mean molecular mass of the substance. The molecular mass of CO2 = 12+2x16 = 44, so the mass of a mole of CO2 is approximalty 44 grams

Explanation:

3 0
3 years ago
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