Answer:
The final volume is 6.4 L.
Explanation:
Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.
In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.
In a dilution the expression is used:
Ci*Vi = Cf*Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci: 8 M
- Vi: 2 L
- Cf: 2.5 M
- Vf: ?
Replacing:
8 M* 2 L= 2.5 M* Vf
Solving:
Vf=6.4 L
<u><em>The final volume is 6.4 L.</em></u>
Answer: these are the values of density that complete the table
Sample density
A 1024
B 1027
C 1026
D 1025
E 1028
Procedure: take the values of temperature and salinity for each sample given in the table, and enter the graph to read the corresponding density value.
1) Sample A: temp = 21°C, salinity = 34%
Locate the value 34 on the horizontal axis (salinity axis), move vertically upward until reaching the level of 21 for the vertical axis, read the value of the density on the curve that passes through the point (34, 21). That value is
density = 1024 g/cm^3.
That is the value to copy on the table.
2) Sample B: temp = 11°C, salinity =35 %
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 11 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 11). That value is
density = 1027 g/cm^3.
That is the value to copy on the table.
3) Sample C: temp = 12°C, salinity = 34%
Locate the value 34 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 12 for the vertical axis,
read the value of the density on the curve that passes through the point
(34, 12). That value is
density = 1026 g/cm^3.
That is the value to copy on the table.
4) Sample D: temp = 19°C, salinity = 35%
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 19 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 19). That value is
density = 1025 g/cm^3.
That is the value to copy on the table.
5) Sample E: temp = 3°C, salinity = 35%
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 3 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 3). That value is
density = 1028 g/cm^3.
That is the value to copy on the table.
Answer:
The correct movement would be -
1. Water - into solution A.
2. NaCl - into solution A.
3. glucose - into Solution B.
4. Albumin - neither.
Explanation:
All the substances are separated by the semipermeable membrane and the semipermeable membrane allows the only small molecule to pass through it. So the movement of the given substance would be -
1. Water - into solution A.
Water molecules are small and can easily pass through the semipermeable membrane as it is given that the solution b has low solute concentration and solution A has high solute concentration. It is known that the movement of the solvent always takes place from low solute concentration to high so the movement of water will be into solution A.
2. NaCl - into solution A.
The movement of small ionic molecule NaCl is always from high to low concentration as it is given that solution B has high concentration than solution A so movement will take place into solution A.
3. glucose - into Solution B.
It is also a small molecule and moves from the high glucose region to the low glucose concentration region, in solution A the concentration of glucose is high than solution B so movement would be into solution B.
4. Albumin - neither.
Albumin is a protein which is macromolecule and large in size to pass through the semipermeable membrane so, albumin move neither solution A nor solution B.
Answer: 1.15 moles
Explanation:
1 mole = 6.02214076*10^23 molecules