Answer:
non-polar covalent bonds
this is when the electronegativity difference between the two non-metal atoms is very little to cause a partial charge (delta positive and delta negative; δ+ and δ-) on the atoms
The answer for the following problem is mentioned below.
Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>
Explanation:
Given:
ΔH = -393.5 kJ/ mol
ΔS =0.0029 kJ/mol K
T = 298 K
To solve:
Gibbs free energy (ΔG)
We know;
<u>ΔG = ΔH - TΔS </u>
ΔG = -393.5 - (298 × 0.0029)
ΔG = -393.5 - 0.8642
<u><em>ΔG = -394.36 J</em></u>
Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>
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Answer: The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
Explanation:
Chemical compounds that have conjugated planar ring systems where there are delocalized pi-electron clouds are present in place of individual alternate and single bonds.
This means that electrons present in a double bond of alkene are in conjugation.
Therefore, we can conclude that the double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.