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strojnjashka [21]
2 years ago
14

Express the pressure 545 mm Hg in kilopascals.

Chemistry
1 answer:
Arlecino [84]2 years ago
6 0

545mm Hg in Kilopascals is 72.6607

I hope this helps you. Good luck stay safe, healthy and, happy!<3

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7. Ionic bonds are at one end of the bond spectrum. What kinds of bonds are at the other end?
blondinia [14]

Answer:

non-polar covalent bonds

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Which of the following elements makes up the tissues and organs of animals? A.Carbon B.Hydrogen C. Nitrogen D.Oxygen
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Hydrogen if im wrong by texting me 

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4 years ago
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What is deltaG at 298 K for the reaction <br> C + O2 = CO
blondinia [14]

The answer for the following problem is mentioned below.

Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>

Explanation:

Given:

ΔH = -393.5 kJ/ mol

ΔS =0.0029 kJ/mol K

T = 298 K

To solve:

Gibbs free energy (ΔG)

We know;

<u>ΔG = ΔH - TΔS </u>

ΔG  = -393.5 - (298 × 0.0029)

ΔG = -393.5 - 0.8642

<u><em>ΔG = -394.36 J</em></u>

Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>

<u><em></em></u>

8 0
3 years ago
When a glucose molecule loses a hydrogen atom in an oxidation-reduction reaction, the glucose molecule is ________
sineoko [7]

Answer:

Important

Explanation:

3 0
2 years ago
The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be ____ and are
Dima020 [189]

Answer: The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.

Explanation:

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This means that electrons present in a double bond of alkene are in conjugation.

Therefore, we can conclude that the double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.

7 0
3 years ago
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