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Delicious77 [7]
3 years ago
11

What are various paradox related to time travel?​

Physics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

This is a paradox — an inconsistency that often leads people to think that time travel cannot occur in our universe." A variation is known as the "grandfather paradox" — in which a time traveler kills their own grandfather, in the process preventing the time traveler's birth

Explanation:

hope this Wil help ....

You might be interested in
Waldo gets stopped by the police.
STALIN [3.7K]

Answer:

At least they found him.

Explanation:

3 0
2 years ago
A 0.9 kg ball attached to a cord is whirled in a vertical circle of radius 2.5 m. Find the minimum speed needed at the top of th
lapo4ka [179]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

K =U_{g} (1)

Where:

K - Translational kinetic energy, measured in joules.

U_{g} - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h

v = \sqrt{2\cdot g\cdot h} (2)

Where:

m - Mass, measured in kilograms.

v - Initial speed, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

h - Maximum height of the ball, measured in meters.

If we know that g = 9.807\,\frac{m}{s^{2}} and h = 5\,m, then the initial speed of the ball is:

v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}

v\approx 9.903\,\frac{m}{s}

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

3 0
3 years ago
plz i need help fast................a motion along a straight line with a constant increase in velocity is ?​
Monica [59]

Answer:

uniform acceleration

Explanation:

The definition for uniform acceleration is:

if an object travels in  a straight line and its velocity increases or decreases by equal amounts in equal intervals of time, then the acceleration is said to be uniform.

Hope this helps.

Good Luck

8 0
4 years ago
Read 2 more answers
Name two important differences between light waves and sound waves
emmasim [6.3K]

Answer:

1. Light is electromagnetic waves while sound is mechanical.

Light wave is transverse and sound is longitudinal.

Explanation:

2.

<i = <r

3.

when distance between source and obstacle and distance between obstacle and screen is finite then the diffraction is fresnal diffraction

when distance between source and obstacle and distance between obstacle and screen is infinite then the diffraction is Fraunhofer's diffraction

8 0
3 years ago
Consider a single turn of a coil of wire that has radius 6.00 cm and carries the current I = 1.50 A . Estimate the magnetic flux
Fofino [41]

Answer:

a

  \phi = 1.78 *10^{-7} \  Weber

b

 L  = 1.183 *10^{-7} \  H

Explanation:

From the question we are told that

   The radius is  r = 6 \ cm =  \frac{6}{100} =  0.06 \ m

   The current it carries is  I  = 1.50 \ A

     

The  magnetic flux of the coil is mathematically represented as

       \phi = B  * A

Where  B is the  magnetic field which is mathematically represented as

         B  =  \frac{\mu_o  * I}{2 *  r}

Where  \mu_o is the magnetic field with a constant value  \mu_o  =  4\pi * 10^{-7} N/A^2

substituting  value

          B  =  \frac{4\pi * 10^{-7}   * 1.50 }{2 *  0.06}

          B  =  1.571 *10^{-5} \ T

The area A is mathematically evaluated as

       A  = \pi r ^2

substituting values

       A  = 3.142 *  (0.06)^2

       A  = 0.0113 m^2

the magnetic flux is mathematically evaluated as    

        \phi = 1.571 *10^{-5} * 0.0113

         \phi = 1.78 *10^{-7} \  Weber

The self-inductance is evaluated as

       L  =  \frac{\phi }{I}

substituting values

        L  =  \frac{1.78 *10^{-7} }{1.50 }

         L  = 1.183 *10^{-7} \  H

7 0
3 years ago
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