Answer:
True
Explanation:
The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.
The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.
Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.
Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.
<span>When looking at nuclear masses we speak of the processes nuclear fision and nuclear fusion. </span>In fission a nucleus breaks up, into two nuclei. In fusion on the other hand two light nuclei combine to form one heavier nucleus. The relation
E=m*c^2. explains the difference in masses. <span>
So, in case of nuclear fusion t</span><span>he mass of the parts is always </span>more than the mass of the whole when looking at nuclear masses. In case of nuclear fusion. And in case of nuclear fision, the mass of the parts is always less<span> than the mass of the whole when looking at nuclear masses. In case of nuclear fusion</span>
Answer:
During the experiment, alpha particles bombarded a thin piece of gold foil. The alpha particles were expected to pass easily through the gold foil. ... The discovery of the nucleus was a result of Rutherford's observation that a small percentage of the positively charged particles bombarding the metal's surface...
Explanation:
jayfeather friend me
Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :


p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s
Answer:
The arrow will bury itself farther by 3S₁
Explanation:
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lets assume; the Arrow shot by me has a speed twice the speed of the arrow fired by the younger shooter
Given that ; acceleration is constant , Frictional force is constant
A₂ = A₁
Vf²₂ - Vi²₂ / 2s₂ = Vf₁² - Vi₁² / 2s₁ ---- ( 1 )
final velocities = 0
Initial velocities : Vi₂ = 2(Vi₁ )
Back to equation 1
0 - (2Vi₁ )² / 2s₂ = 0 - Vi₁² / 2s₁
hence :
s₂ = 4s₁
hence the Arrow shot by me will burry itself farther by :
s₂ - s₁ = 3s₁
<em>Note : S1 = distance travelled by the arrow shot by the younger shooter</em>