If you have a picture of the problem I can answer it so just send a pic of the math problem
Answer:
Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 300
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 300
3X + 3 = 300
3X + 3 - 3 = 300 - 3
3X = 297
3X/3 = 297/3
X = 99
Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.
99 + 100 + 101 = 300
We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.
Step-by-step explanation:
Answer:
x = 27
y = 29
Step-by-step explanation:
Answer:
x=1 and y= 6
Step-by-step explanation:
and for y its a positive cause their both negitives
Answer:
6000000000
Step-by-step explanation:
Given the following question:
![6,010,499,999](https://tex.z-dn.net/?f=6%2C010%2C499%2C999)
<u>Find the billions place value:
</u>
![billions=6](https://tex.z-dn.net/?f=billions%3D6)
<u>Round to the nearest billion:</u>
![6,010,499,999](https://tex.z-dn.net/?f=6%2C010%2C499%2C999)
![0](https://tex.z-dn.net/?f=0%3C5)
![6000000000](https://tex.z-dn.net/?f=6000000000)
Your answer is "6000000000."
Hope this helps.