All categories

3 years ago

How to write four hundred two million seventy-three thousand one hundred eighty in standard form

Mathematics

2 answers:

ziro4ka [17]3 years ago

5 0

Four hundred two million seventy-three thousand one hundred eighty in standard form: 402,073,180 would be your answer

umka21 [38]3 years ago

4 0

402,073,180!!!!!!!!!!!!!!! :-)

You might be interested in

Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is

CaHeK987 [17]

Answer:

The System of equation is $x+y=29, 5x + 2y = 100$ .

Step-by-step explanation:

Given:

Let 'x' be the number of questions worth 5 points.

Let 'y' be the number of questions worth 2 points

Total Number of Problems = 29

So the Total Number of Problems is equal to sum of the number of questions worth 5 points and the number of questions worth 2 points.

Framing in equation form we get;

$x+y=29$ .

Also Given:

Test is of Total Points = 100

Now Total points in test is equal to sum of the number of questions worth 5 points multiplied by and the number of questions worth 2 points multiplied by 2.

Framing in equation form we get;

$5x+2y=100$

Hence The System of Equations are $\left \{ {{x+y=29} \atop {5x+2y=100}} \right.$ .

7 0

3 years ago

Read 2 more answers

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

Lilit [14]

Check the picture below.

$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$

7 0

3 years ago

Read 2 more answers

Can someone help me with this problem???

Ber [7]

1. linear equation

2. rearrange the equation so 4y = 12 - 3× and then divide both sides by 4 to get:
y = 3 - 3/4×

3. equation of a straight line / linear equation

4. gradient is + 3

5. not sure sorry

6. 3x = 12 - 4y. Divide each side by 3 to get:
x = 4 - 4/3y

7. use y = 3 - 3/4x by doing and x and y table. So when x = 1, y = 3 - 3/4 (1) (replace the x which the x value you've chosen). Then plot.

8. Make up any problem such as weather, food, etc.

Hope that helps !

8 0

3 years ago

Evaluate.<br><br> (1/4)^-2 - (5^0x2) x 1^-1

blondinia [14]

Answer:

Step-by-step explanation:

Arithmetic expressions are best evaluated using a reliable calculator. The Google calculator always follows the Order of Operations, so can give you a good answer to such questions.

(1/4)^-2 - (5^0)(2)(1^-1)

= 16 - (1)(2)(1) . . . . evaluate the exponents first

= 16 -2 . . . . . . . . . evaluate the product next

= 14 . . . . . . . . . . . finally, evaluate the sum

___

The rule of exponents is ...

a^-b = 1/(a^b)

4 0

3 years ago

You pick a marble pick a card and spin the spinner how many outcomes are possible

Katen [24]

SOLUTION:

For the marbles, 4 outcomes are possible.

For the cards, 2 outcomes are possible.

For the spinner, 2 outcomes are possible.

Thus, the total outcomes possible are;

$4\times2\times2=16\text{ ways}$

Thus there are 16 possible outcomes.

3 0

1 year ago