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Nadusha1986 [10]
2 years ago
12

?Al + ?H2SO4 → ?Al2(SO4)3 +3H2

Chemistry
1 answer:
AfilCa [17]2 years ago
5 0

The answer is: 27 grams of aluminium.

Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

n(H₂) = 1.5 mol; amount of hydrogen.

Form chemical reaction: n(Al) : n(H₂) = 2 : 3.

n(Al) = 2 · 1.5 mol ÷ 3.

n(Al) = 1.0 mol; amount of aluminium.

m(Al) = n(Al) · M(Al).

m(Al) = 1 mol · 27 g/mol.

m(Al) = 27 g; mass of aluminium.

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To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

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<span>vA = speed of diffusion of A  (HBR)</span>

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6 0
3 years ago
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2 years ago
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