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Lady_Fox [76]
3 years ago
12

Suppose a piano tuner hears 3 beats per sec-

Physics
1 answer:
vova2212 [387]3 years ago
8 0

Answer: 3 The string should be loosened because  the frequency of the string is 5 Hz above the  correct frequency.

Explanation:  In order to explain this problem we have to consider the relationship bewteen the Tension and the frequency, this is given by:

We know that:

v=\sqrt{T/\mu where μ and T are the mass linear density and Tension of teh string, respectively.

We also know that v=λ*ν the speed is related to the wavelength (λ) and the frequency (ν).

Then we have that frequency depents  directely of the Tension (T) on the string.

In our case the frequency to be tuned is 3 Hz, firstly the piano tuner slightly tightening then he  hears 5 beats per second (5 Hz). Then it is neccesary loose the tension on the string because the actual frequency is above to the correct frequency (3 Hz).

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Bezzdna [24]

Answer:

In the more scientific viewpoint, the most important thing that she must do is caring for her hygiene and put some plastic gloves in her hands.

This is because there are lots of particles that can be retained in the hands (dust, skin, etc), and when examining the scene, she may drop some of these particles, "contaminating" the scene in this way with information that only will affect the investigation.

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7 0
3 years ago
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What condition is required for cloud formation in the atmosphere?
Vedmedyk [2.9K]

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The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.724 W/m2. What is the maximum va
Hitman42 [59]

Answer:

7.78x10^-8T

Explanation:

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S = (1/μ0) E × B

at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,

S = (1/μ0) E B

where S, E and B are magnitudes. The average value of the Pointing Vector is

<S> = [1/(2 μ0)] E0 B0

where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)

Also at any instant,

E = c B

where E and B are magnitudes, so it must also be true at the instant of peak values

E0 = c B0

Substituting for E0,

<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²

Solve for B0.

Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)

= 7.79 x10 ^-8 T

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3 years ago
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Answer:

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Explanation:

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2 years ago
If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 50 km/h . The c
PtichkaEL [24]

Answer:

Explanation:

v = 50 km / h

= 13.89 m /s

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static friction = μs mg

centripetal force = m v² / R

m v² / R = μs mg

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= 28.12 m .

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