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Lady_Fox [76]
3 years ago
12

Suppose a piano tuner hears 3 beats per sec-

Physics
1 answer:
vova2212 [387]3 years ago
8 0

Answer: 3 The string should be loosened because  the frequency of the string is 5 Hz above the  correct frequency.

Explanation:  In order to explain this problem we have to consider the relationship bewteen the Tension and the frequency, this is given by:

We know that:

v=\sqrt{T/\mu where μ and T are the mass linear density and Tension of teh string, respectively.

We also know that v=λ*ν the speed is related to the wavelength (λ) and the frequency (ν).

Then we have that frequency depents  directely of the Tension (T) on the string.

In our case the frequency to be tuned is 3 Hz, firstly the piano tuner slightly tightening then he  hears 5 beats per second (5 Hz). Then it is neccesary loose the tension on the string because the actual frequency is above to the correct frequency (3 Hz).

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hjlf

Answer:

4200 Joules

Explanation:

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Using the above formula, we have

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2 years ago
HELPPPPP !!!!
Nataly [62]

Your answer is C)

a)t=2.78 sec

b)R=835.03 m

c)

Explanation:

Given that

h= 38 m

u=300 m/s

here given that

The finally y=0

So

t=2.78 sec

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2 years ago
The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​
spin [16.1K]

Answer:

P = 0.0644 atm

Explanation:

Given that,

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We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

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1 torr = (1/760) atm

49 torr = (49/760) atm

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Hence, the presssure of the sample of gas is equal to 0.0644 atm.

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