Suppose a piano tuner hears 3 beats per sec-
1 answer:
Answer: 3 The string should be loosened because the frequency of the string is 5 Hz above the correct frequency.
Explanation: In order to explain this problem we have to consider the relationship bewteen the Tension and the frequency, this is given by:
We know that:
where μ and T are the mass linear density and Tension of teh string, respectively.
We also know that v=λ*ν the speed is related to the wavelength (λ) and the frequency (ν).
Then we have that frequency depents directely of the Tension (T) on the string.
In our case the frequency to be tuned is 3 Hz, firstly the piano tuner slightly tightening then he hears 5 beats per second (5 Hz). Then it is neccesary loose the tension on the string because the actual frequency is above to the correct frequency (3 Hz).
You might be interested in
Given :
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.
To Find :
The coefficient of static friction between the box and the plane.
Solution :
Vertical component of force :
Horizontal component of force(Normal reaction) :
Since, box is on the verge of slipping :
Therefore, the coefficient of static friction between the box and the plane is 1.07.
Hence, this is the required solution.