ans: B
Kinetic energy = ![\frac{1}{2} mv^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D)
= ![\frac{1}{2} (4)(5^{2} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%284%29%285%5E%7B2%7D%20%29)
= 50J
ps. the height will only affect its potential energy, not kinetic.
Answer:
L= 2 mH
Explanation:
Given that
Frequency , f= 10 kHz
Maximum current ,I = 0.1 A
Maximum energy stored ,E= 1 x 10⁻⁵ J
The maximum energy stored in the inductor is given as follows
![E=\dfrac{1}{2}LI^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7DLI%5E2)
Where ,L= Inductance
I=Current
E=Energy
Now by putting the values in the above equation
![10^{-5}=\dfrac{1}{2}\times L\times 0.1^2](https://tex.z-dn.net/?f=10%5E%7B-5%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20L%5Ctimes%200.1%5E2)
![L=\dfrac{2\times 10^{-5}}{0.1^2}\ H](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7B2%5Ctimes%2010%5E%7B-5%7D%7D%7B0.1%5E2%7D%5C%20H)
L=0.002 H
L= 2 mH
We know that frequency f is given as
![2\pi f=\dfrac{1}{\sqrt{LC}}](https://tex.z-dn.net/?f=2%5Cpi%20f%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D)
C=Capacitance , f=frequency ,L=Inductance
Now by putting the values
![2\pi \times 10\times 10^3=\dfrac{1}{\sqrt{0.002\times C} }](https://tex.z-dn.net/?f=2%5Cpi%20%5Ctimes%2010%5Ctimes%2010%5E3%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7B0.002%5Ctimes%20C%7D%20%7D)
![62831.85=\dfrac{1}{\sqrt{0.002\times C}}](https://tex.z-dn.net/?f=62831.85%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7B0.002%5Ctimes%20C%7D%7D)
![\sqrt{0.002\times C=\dfrac{1}{62831.85}](https://tex.z-dn.net/?f=%5Csqrt%7B0.002%5Ctimes%20C%3D%5Cdfrac%7B1%7D%7B62831.85%7D)
![0.002\times C=0.0000159^2](https://tex.z-dn.net/?f=0.002%5Ctimes%20C%3D0.0000159%5E2)
![C=\dfrac{0.0000159^2}{0.002}\ F](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B0.0000159%5E2%7D%7B0.002%7D%5C%20F)
![C=1.26\times 10^{-7}\ F](https://tex.z-dn.net/?f=C%3D1.26%5Ctimes%2010%5E%7B-7%7D%5C%20F)
Therefore the inductance and capacitance will be 2 mH and 1.26 x 10⁻⁷ F respectively.
Answer:
2.98 m/s^2
Explanation:
I have done this before and it was a question on my physics test
Magnets facing the same way <span />