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3 years ago

How to find the velocity of an object in a circular path?

2 answers:

8 0

Distance of an object in a circular path is equal to the circumference of the circular path, so the formula to find speed is -

Speed = $\frac{2 \pi r}{Time}$
Speed is there because velocity keeps changing continuously, because of the change of direction.

Luda [366]3 years ago

7 0

First of all, let's just talk about the speed, and not get wound up
in the velocity. OK ?

If a fly is sitting on the rim of the wheel and the wheel is rotating, then for
each full revolution of the wheel, the fly travels the circumference of the
wheel, which is (2 π) x (radius of the wheel).

In 'N' revolutions, the fly travels (2 N π) x (the radius). and so on.

So if the wheel is going, let's say 71 revs per minute (RPM), a point
on the rim is moving at (2 π times 71) x (the radius) per minute.

Another way to say it:

Speed of a point on the circle = (2 π) x (rotation frequency) x (radius).

The 'rotation frequency' takes care of the unit of time, and the 'radius'
takes care of the unit of length, so the result is a speed.

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Do y’all know what A is?! I really need help!

Naily [24]

It is the crest/peak.

6 0

3 years ago

A proton accelerates from rest in a uniform electric field of 680 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativis

Ksivusya [100]

Answer:

Acceleration, $a=6.51\times 10^{10}\ m/s^2$

Explanation:

Given that,

Electric field, E = 680 N/C

Speed of the proton, v = 1.3 Mm/s

We need to find the acceleration of the proton. We know that the force due to motion is balanced by the electric force as :

$qE=ma$

a and m are the acceleration and mass of the proton.

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 680}{1.67\times 10^{-27}}$

$a=6.51\times 10^{10}\ m/s^2$

So, the acceleration of the proton is $a=6.51\times 10^{10}\ m/s^2$ . Hence, this is the required solution.

3 0

3 years ago

An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the accelerati

rosijanka [135]

Answer:

A) $\frac{g}{b}(1-e^{-bt})$

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since $\frac{dv}{dt}= g - bv = b( \frac{g}{b} - v)$ ⇒ $\frac{dv}{ \frac{g}{b} - v}= bdt$

So take the integral of both side.

$- ln (\frac{g}{b} - v) = bt + C$

Since for t=0, v = 0 ⇒ $C =- ln (\frac{g}{b})$

$v = \frac{g}{b} + e^{-bt-ln(\frac{g}{b})} = \frac{g}{b}- \frac{g}{b}e^{-bt} = \frac{g}{b}(1-e^{-bt})$

5 0

3 years ago

IF it possible for an object to move for 10 seconds at a high speed and end up with an average velocity of zero? true or false

marishachu [46]

True, if you move something forward at 100 miles an hour but your on something moving backwards 100 miles an hour you up staying in the same location, aka zero velocity.

4 0

3 years ago

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Which of the circuit offers greater resistance to the flow of current 1A or 2A ?

Dafna1 [17]

1 A offers greater resistance

7 0

3 years ago

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